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likoan [24]
3 years ago
15

(Please help 15 points the assignment is late) (multiple questions) (everything is virtual task )

Chemistry
1 answer:
Brilliant_brown [7]3 years ago
7 0

Answer:

Hypothesis and Data Collection

Part A-i think the glass with cold water will have more of a air bubble effect then the one with hot water

Part B-The glass with cold water is having more of a reaction but the water level in both of them are the same

Part C-yes, the glass with cold water had more of a reaction then the one with hot water

Analyze and Extend

Part A-yes, the glass with cold water had more of a reaction then the one with hot water

Part B-Becuase the reaction in the cold water was greater than the one in the hot water we can come to the conclusion that CO2 has a higher solubility in cold water  

Part C-the soda that was left in the refrigerator wil have more "fizzing and bubbles" becuase it has higher solubility then the one left in the hot sun

Part D-There is now too much CO2 in the atmosphere and the tempertaures will continue to increase (this is why the summer time is hotter then the rest of the year)

Ik i was late to answer this but can you please give me brainliest

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The PbI₂ <em>just begin to precipitate when the product  [Pb²⁺] [I⁻]² = 1.4x10⁻⁸</em>

<em />

As the initial [Pb²⁺] = 0.0050M:

[Pb²⁺] [I⁻]² = 1.4x10⁻⁸

[0.0050] [I⁻]² = 1.4x10⁻⁸

[I⁻]² = 1.4x10⁻⁸ / 0.0050

[I⁻]² = 2.8x10⁻⁶

<h3>[I⁻] = 1.67x10⁻³</h3><h3 />

So, as the [I⁻] concentration is also in the expression of Ksp of AgI and you know concentration in solution of I⁻ = 1.67x10⁻³M:

[Ag⁺] [I⁻] = 8.3x10⁻¹⁷

[Ag⁺] [1.67x10⁻³] = 8.3x10⁻¹⁷

<h3>[Ag⁺] = 5.0x10⁻¹⁴M</h3>

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