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Over [174]
3 years ago
14

A hot lump of 35.8 g of copper at an initial temperature of 70.7 °C is placed in 50.0 mL H2O initially at 25.0 °C and allowed to

reach thermal equilibrium. What is the final temperature of the copper and water, given that the specific heat of copper is 0.385 J/(g·°C)? Assume no heat is lost to surroundings.

Physics
1 answer:
AURORKA [14]3 years ago
4 0

I upload the answer via Image because Brainly warned me that there were inappropriate links or words.

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A car is designed to get its energy from a rotating
nydimaria [60]

Answer:

(a). The kinetic energy stored in  the fly wheel is 46.88 MJ.

(b). The time is 1.163 hours.

Explanation:

Given that,

Radius = 1.50 m

Mass = 475 kg

Power P= 15.0 hp = 15.0\times746=11190 watt

Rotational speed = 4000 rev/min

We need to calculate the moment of inertia

Using formula of moment of inertia

I=\dfrac{1}{2}mr^2

Put the value into the formula

I=\dfrac{1}{2}\times475\times(1.50)^2

I=534.375\ kg m^2

(a). We need to calculate the kinetic energy stored in  the fly wheel

Using formula of K.E

K.E=\dfrac{1}{2}I\omega^2

Put the value into the formula

K.E = \dfrac{1}{2}\times534.375\times(4000\times\dfrac{2\pi}{60})^2

K.E=46880620.9\ J

K.E =46.88\times10^{6}\ J

K.E =46.88\ MJ

(b). We need to calculate the length of time the car could run before the flywheel  would have to be brought backup to speed

Using formula of time

t=\dfrac{46.88\times10^{6}}{11190}

t=4189.45\ sec

t=1.163\ hours

Hence, (a). The kinetic energy stored in  the fly wheel is 46.88 MJ.

(b). The time is 1.163 hours.

3 0
3 years ago
If Chris drives 27 km N and then 40 km E , what is the distance and displacement
Bas_tet [7]
The answer would be 13.
3 0
3 years ago
A spring that is compressed 14.5 cm from its equilibrium position stores 2.99 J of potential energy. Determine the spring consta
strojnjashka [21]

Answer:

284.4233 N/m

Explanation:

k = Spring constant

x = Compression of spring = 14.5 cm

U = Potential energy = 2.99 J

The potential energy of a spring is given by

U=\dfrac{1}{2}kx^2

Rearranging to get the value of k

\\\Rightarrow k=\dfrac{2U}{x^2}\\\Rightarrow k=\dfrac{2\times 2.99}{0.145^2}\\\Rightarrow k=284.4233\ N/m

The spring constant is 284.4233 N/m

7 0
3 years ago
The normal force which the path exerts on a particle is always perpendicular to the _________________ tangent to the path. trans
Marianna [84]
Tangent to the pathh.
7 0
3 years ago
Calculate the Force of Gravity acting on an object that has a mass of 1.3 kg. The object is on Earth so use 9.8m/s2 for the acce
sweet-ann [11.9K]
To calculate the gravitational force acting on an object given the mass and the acceleration due to gravity, use the following formula.

Fg = m • g
Fg = 1.3 kg • 9.8 m/s^2
Fg = 12.74 N or about 12.7 N.

The solution is C. 12.7 N.
7 0
2 years ago
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