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3 years ago

A car has an acceleration of -5 m/s^2. Describe the car’s motion

Physics

1 answer:

AlladinOne [14]3 years ago

7 0

Explanation:

because the acceleration is negative, this indicates a deceleration (or slowing down) . Hence we can say that:

The car is decelerating (slowing down), i.e its velocity is decreasing, at a constant rate of 5m/s².

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A velocity-time graph shows how what changes over time.

Mnenie [13.5K]

Answer:

velocity changes over time.

6 0

3 years ago

An eagle carrying a trout flies above a lake along a horizontal path. The eagle drops the trout from a height of 6.1 m. The fish

Snezhnost [94]

Answer:

7.1 m/s

Explanation:

First, find the time it takes for the fish to reach the water.

Given in the y direction:

Δy = 6.1 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

6.1 m = (0 m/s) t + ½ (9.8 m/s²) t²

t = 1.12 s

Next, find the velocity needed to travel 7.9 m in that time.

Given in the x direction:

Δx = 7.9 m

a = 0 m/s²

t = 1.12 s

Find: v₀

Δx = v₀ t + ½ at²

7.9 m = v₀ (1.12 s) + ½ (0 m/s²) (1.12 s)²

v₀ = 7.1 m/s

4 0

3 years ago

Read 2 more answers

A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 3.9 m/s. The car is a distanc

sammy [17]

If it takes $t$ seconds to reach the car, then the distance $d$ is $3.9t$ .

The bear's distance from the tourist's starting point is
$6t-23$

For maximum $d$ , we set the equations equal to each other:
$3.9t=6t-23$
$\Rightarrow -2.1t=-23$
$\Rightarrow t=\frac{23}{2.1}$
so the distance is
$d=3.9(\frac{23}{2.1})\approx42.741\ m$

6 0

3 years ago

There is a 3-kg toy cart moving at 4 m/s. Calculate the kinetic energy of the cart.

m_a_m_a [10]

The kinetic energy of the cart is 24 J.

Explanation:

The acceleration of a given mass from rest to the velocity is known as kinetic energy. It gains energy from acceleration and remains in this state until the speed of the object changes.

The kinetic energy is the given by,

K.E = 1/2 mv^2

Given the mass m = 3 kg, v = 4 m / s.

K.E = 1/2 $\times$ 3 $\times$ (4)^2

K.E = 24 J.

5 0

3 years ago

An object of mass 3.4 kg is moving in a straight line with kinetic energy 59.177 J. A force is applied in the direction of its m

rusak2 [61]

Answer:

Its momentum is multiplied by a factor of 1.25

Explanation:

First, we calculate the initial velocity of the object:

K = 0.5 * m * v₁²

59.177 J = 0.5 * 3.4 kg * v₁²

v₁ = 5.9 m/s

With that velocity we can calculate the initial momentum of the object:

p₁ = v₁ * m

p₁ = 20.06 kg·m/s

Then we calculate the velocity of the object once its kinetic energy has increased:

(59.177 J) * 1.57 = 0.5 * 3.4 kg * v₂²

v₂ = 7.4 m/s

And calculate the second momentum of the object:

p₂ = v₂ * m

p₂ = 25.16 kg·m/s

Finally we calculate the factor:

p₂/p₁ = 1.25

3 0

2 years ago