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Nataliya [291]
2 years ago
13

If two proton approach each other with speed of 400m\s and 450m\s respectively what is the total momentum of the two particle sy

stem
Physics
1 answer:
lilavasa [31]2 years ago
7 0

Answer: 83.65\times 10^{-27}\ kg.m/s

Explanation:

Given

The velocities of the protons are 400 m/s and 450 m/s

Mass of the Proton is m=1.673\times 10^{-27}\ kg

Since they travel in the opposite direction, therefore, their momentum cancels out each other.

Momentum is the product of mass and velocity

\therefore m(450-400)\\\Rightarrow 1.673\times 10^{-27}\times 50\\\Rightarrow 83.65\times 10^{-27}\ kg.m/s

The direction of momentum is in the direction of proton having 450 m/s velocity.

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Answer:

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Answer:

\theta = 106.3 degree

Explanation:

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also we can find the magnitude of two vectors as

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