Answer:
Part a)
![a_c = 1.67 \times 10^{-10} m/s^2](https://tex.z-dn.net/?f=a_c%20%3D%201.67%20%5Ctimes%2010%5E%7B-10%7D%20m%2Fs%5E2)
Part b)
![v = 2.18 \times 10^5 m/s](https://tex.z-dn.net/?f=v%20%3D%202.18%20%5Ctimes%2010%5E5%20m%2Fs)
Explanation:
Time period of sun is given as
![T = 2.60 \times 10^8 years](https://tex.z-dn.net/?f=T%20%3D%202.60%20%5Ctimes%2010%5E8%20years)
![T = 2.60 \times 10^8 (365 \times 24 \times 3600) s](https://tex.z-dn.net/?f=T%20%3D%202.60%20%5Ctimes%2010%5E8%20%28365%20%5Ctimes%2024%20%5Ctimes%203600%29%20s)
![T = 8.2 \times 10^{15} s](https://tex.z-dn.net/?f=T%20%3D%208.2%20%5Ctimes%2010%5E%7B15%7D%20s)
Now the radius of the orbit of sun is given as
![R = 3.00 \times 10^4 Ly](https://tex.z-dn.net/?f=R%20%3D%203.00%20%5Ctimes%2010%5E4%20Ly)
![R = 3.00 \times 10^4 (3\times 10^8)(365 \times 24 \times 3600)m](https://tex.z-dn.net/?f=R%20%3D%203.00%20%5Ctimes%2010%5E4%20%283%5Ctimes%2010%5E8%29%28365%20%5Ctimes%2024%20%5Ctimes%203600%29m)
![R = 2.84 \times 10^20 m](https://tex.z-dn.net/?f=R%20%3D%202.84%20%5Ctimes%2010%5E20%20m)
Part a)
centripetal acceleration is given as
![a_c = \omega^2 R](https://tex.z-dn.net/?f=a_c%20%3D%20%5Comega%5E2%20R)
![a_c = \frac{4\pi^2}{T^2} R](https://tex.z-dn.net/?f=a_c%20%3D%20%5Cfrac%7B4%5Cpi%5E2%7D%7BT%5E2%7D%20R)
![a_c = \frac{4\pi^2}{(8.2\times 10^{15})^2}(2.84 \times 10^{20})](https://tex.z-dn.net/?f=a_c%20%3D%20%5Cfrac%7B4%5Cpi%5E2%7D%7B%288.2%5Ctimes%2010%5E%7B15%7D%29%5E2%7D%282.84%20%5Ctimes%2010%5E%7B20%7D%29)
![a_c = 1.67 \times 10^{-10} m/s^2](https://tex.z-dn.net/?f=a_c%20%3D%201.67%20%5Ctimes%2010%5E%7B-10%7D%20m%2Fs%5E2)
Part b)
orbital speed is given as
![v = \frac{2\pi R}{T}](https://tex.z-dn.net/?f=v%20%3D%20%5Cfrac%7B2%5Cpi%20R%7D%7BT%7D)
![v = \frac{2\pi (2.84 \times 10^{20})}{8.2 \times 10^{15}}](https://tex.z-dn.net/?f=v%20%3D%20%5Cfrac%7B2%5Cpi%20%282.84%20%5Ctimes%2010%5E%7B20%7D%29%7D%7B8.2%20%5Ctimes%2010%5E%7B15%7D%7D)
![v = 2.18 \times 10^5 m/s](https://tex.z-dn.net/?f=v%20%3D%202.18%20%5Ctimes%2010%5E5%20m%2Fs)
It is C. A description goes into the details about something, and an explanation is a statement that clarifies something, generally a question.
The pressure of the air inside the balloon is higher than outside, and when you pop the balloon, the high pressure air expands quickly and makes a popping sound.
Answer:
0.96 m, upward
Explanation:
![\theta=30^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D30%5E%7B%5Ccirc%7D)
![F=65 N](https://tex.z-dn.net/?f=F%3D65%20N)
![M=5 kg](https://tex.z-dn.net/?f=M%3D5%20kg)
Initial velocity, u=0
![t=0.550 s](https://tex.z-dn.net/?f=t%3D0.550%20s)
![Fcos\theta-Mgsin\theta=Ma](https://tex.z-dn.net/?f=Fcos%5Ctheta-Mgsin%5Ctheta%3DMa)
Where ![g=9.8 m/s^2](https://tex.z-dn.net/?f=g%3D9.8%20m%2Fs%5E2)
Substitute the values
![65cos30-5\times 9.8sin30=5a](https://tex.z-dn.net/?f=65cos30-5%5Ctimes%209.8sin30%3D5a)
![31.8=5a](https://tex.z-dn.net/?f=31.8%3D5a)
![a=\frac{31.8}{5}=6.36 m/s^2](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B31.8%7D%7B5%7D%3D6.36%20m%2Fs%5E2)
![S=ut+\frac{1}{2}at^2](https://tex.z-dn.net/?f=S%3Dut%2B%5Cfrac%7B1%7D%7B2%7Dat%5E2)
![S=0+\frac{1}{2}(6.36)(0.55)^2=0.96 m](https://tex.z-dn.net/?f=S%3D0%2B%5Cfrac%7B1%7D%7B2%7D%286.36%29%280.55%29%5E2%3D0.96%20m)
Hence,the block moves upward because displacement is positive.
Answer:
you can't
Explanation:
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