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3 years ago

2.4 Propene reacts with steam to produce an alcohol, propanol.

Chemistry

1 answer:

qaws [65]3 years ago

7 0

Answer:

C₃H₆ + H₂O = C₃H₈O

Explanation:

Hydration reactions (reactions involving converting an alkene to alcohol) have only one product, so there will be no byproduct along with propanol.

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Write a balanced equation for the combustion of C7H16(l) (heptane) -- i.e. its reaction with O2(g) forming the products CO2(g) a

JulsSmile [24]

Answer:

The standard enthalpy of reaction = -4854.7kJ

The difference: ΔH-ΔE = Δ(PV) = Δn.R.T = 9910.288 J ≈ 9.91 kJ

Explanation:

The balanced chemical equation for the combustion of heptane:

C₇H₁₆ (l) + 11 O₂ (g) → 7 CO₂ (g) + 8 H₂O (l)

Given: The standard enthalpy of formation ( $\Delta H _{f}^{\circ }$ ) for: C₇H₁₆ (l) = -187.8 kJ/mol, O₂ (g) = 0 kJ/mol, CO₂ (g) = -393.5 kJ/mol, H₂O (l) = -286 kJ/mol

To calculate the standard enthalpy of reaction ( $\Delta H _{r}^{\circ }$ ) can be calculated by the Hess's law:

$\Delta H _{r}^{\circ } = \left [\sum \nu \cdot\Delta H _{f}^{\circ }(products) \right ] - \left [\sum \nu\cdot\Delta H _{f}^{\circ }(reactants) \right ]$

Here, $\nu$ is the stoichiometric coefficient

⇒ $\Delta H _{r}^{\circ } =$

$\left [ 7\times \Delta H _{f}^{\circ }\left (CO_{2}\right )+ 8\times \Delta H _{f}^{\circ }\left (H_{2}O \right )\right ]$

$- \left [1\times \Delta H _{f}^{\circ }\left (C_{7}H_{16}\right ) +11\times \Delta H _{f}^{\circ }\left (O_{2} \right ) \right ]$

$=\left [ 7\times \left (-393.5 kJ/mol \right )+ 8\times \left (-286 kJ/mol \right )\right ]$

$-\left [1\times \left (-187.8 kJ/mol \right ) +11\times \left (0 kJ/mol \right ) \right ]$

⇒ $\Delta H _{r}^{\circ } = \left [ \left (-2754.5 \right )+ \left (-2288 \right )\right ]\left -[ \left (-187.8 \right ) +\left (0 \right )\right ]$

⇒ $\Delta H _{r}^{\circ } = \left [ -5042.5 ]\left -[ -187.8] = \left ( -4854.7kJ \right )$

To calculate the difference: ΔH-ΔE=Δ(PV)

We use the ideal gas equation: P.V = n.R.T

⇒ ΔH-ΔE=Δ(PV) = Δn.R.T

Given: Temperature:T = 298K, R = 8.314 J⋅K⁻¹⋅mol⁻¹

Δn = number of moles of gaseous products - number of moles of gaseous reactants = (7)- (11) = (-4)

⇒ ΔH-ΔE=Δ(PV) = Δn.R.T = (-4 mol) × (8.314 J⋅K⁻¹⋅mol⁻¹) × (298K) = 9910.288 J = 9.91 kJ (∵ 1 kJ = 1000J )

8 0

3 years ago

The density of an unknown gas is found to be 4.12 g/L at standard temperature and pressure (STP). What is the molar mass of this

elena-s [515]

The molar mass of this gas is 92.3 g/mol

Calculation

By use ideal gas equation PV =nRT where
n=mole p=pressure V= volume R = gas constant T= temperature

n = mass /molar mass(MM)
substitute in the equation

PV =(mass/MM)RT
mass = density x volume(V)

Therefore PV =(density xV/ MM) xRT

divide both side by by V

P= (density/Mm) xRT

making MM the subject of the formula

MM = densityPRT

At STP = P= 1 atm, R= 0.0821 L.atm/Mol.k T = 273 K

MM is therefore = 4.12 g/l x 1 atm x 0.081 L.atm/mol.k x 273 K = 92.3 g/mol

7 0

3 years ago

Read 2 more answers

List the following elements from increasing electronegativity: boron, magnesium, calcium, chlorine, argon

pishuonlain [190]

Answer:

The list of elements from increasing electronegativity: Calcium < magnesium < chlorine < argon < boron.

Explanation:

In the periodic table if you move from left to right there would be an increase in the electronegativity of the elements. If you move from the bottom to the top of the groups in the periodic table the electronegativity increases and if u move to the bottom from down its decreases.

Calcium is in the 2nd group below magnesium so calcium is the least electronegative among given elements then magnesium and then chlorine as it is top of magnesium then argon, as it is right to the chlorine, and boron has the most electronegativity as it is above rest of the elements.

6 0

3 years ago

Which of the following molecules are considered inorganic?

Oksi-84 [34.3K]

The answer is D water

7 0

2 years ago

Read 2 more answers

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neonofarm [45]

Answer:

Imao ;/