Yeah no one is gonna read all that babe.
Answer:
Two plates pull towards each other
Explanation:
Along a convergent plate boundary, two plates moves towards each other as the move in the same direction.
This results in different forms of plate interactions depending on the plate types.
- At an ocean - ocean and continental - ocean convergent front, subduction of the oceanic plate occurs. This is because the oceanic plate below is denser than the asthenosphere.
- At a continental - continental convergent front, the continental crust is pulls upward and build up as a mountain.
- The subduction produces trenches and some volcanic islands.
Answer:
People may seem and act normally during the fugue, or they may appear moderately bewildered and draw no notice. When the fugue is over, however, people are thrown into a new scenario with no recall of how they got there or what they were doing.
Explanation:
Answer:
619°C
Explanation:
Given data:
Initial volume of gas = 736 mL
Initial temperature = 15.0°C
Final volume of gas = 2.28 L
Final temperature = ?
Solution:
Initial volume of gas = 736 mL (736mL× 1L/1000 mL = 0.736 L)
Initial temperature = 15.0°C (15+273 = 288 K)
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
T₂ = T₁V₂/V₁
T₂ = 2.28 L × 288 K / 0.736 L
T₂ = 656.6 L.K / 0.736 L
T₂ = 892.2 K
K to °C:
892.2 - 273.15 = 619°C
Answer:
At -13 
, the gas would occupy 1.30L at 210.0 kPa.
Explanation:
Let's assume the gas behaves ideally.
As amount of gas remains constant in both state therefore in accordance with combined gas law for an ideal gas-
where 
and 
are initial and final pressure respectively.
and 
are initial and final volume respectively.
and 
are initial and final temperature in kelvin scale respectively.
Here 
, 
, 
, 
and 
Hence 
So at -13 , the gas would occupy 1.30L at 210.0 kPa.
