Answer:
induced dipole-dipole forces or London Dispersion forces / van der Waals forces.
Explanation:
Hexane is non-polar in nature. This is due to :
The bond in the molecule is C-H, which is non-polar in nature because the carbon and the hydrogen having very similar electronegativity values.
Hexane is also symmetric.
The intermolecular force acting in the molecule of the hexane are induced the dipole-dipole forces or London Dispersion forces / van der Waals forces.
Q = mcΔT = (4.00 g)(0.129 J/g•°C)(40.85 °C - 0.85 °C)
Q = 20.6 J of energy was involved (more specifically, 20.6 J of heat energy was absorbed from the surroundings by the sample of solid gold).
The correct answer is option 2. When Pt2+ is reduced it loses electrons, oxidizing it. The oxidation number is the charge of the atom. Adding an electron, decreases the net charge consequently the oxidation number.
<span>Like the previous post states, the number of valence electrons (typically the group number for nonmetals)relates directly to the number of covalent bonds available. Additionally, when you exceed this number you create a cation and when you are less the number of potential bonds, you have created a anion.
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