V=2.90 L
c=1.8 mol/L
n(NaOH)=vc
n(NaOH)=2.90L*1.8mol/L=5.22 mol
Answer:
D) 6.02 kJ/mol
Explanation:
Hello,
In this case, since 200kJ melted 1.5 kg of ice (2.0kg-0.5kg), we can compute the melted moles:

Then, we compute the molar enthalpy of fusion by diving the melted moles to the applied heat:

Hence answer is D) 6.02 kJ/mol.
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answer: 3.40625 moles
Explanation: see the attached pics
Average atomic mass of an element is a sum of the product of the isotope mass and its relative abundance.
For example: Chlorine has 2 isotopes with the following abundances
Cl(35): Atomic mass = 34.9688 amu; Abundance = 75.78%
Cl(37): Atomic mass = 36.9659 amu; Abundance = 24.22 %
Average atomic mass of Cl = 34.9688(0.7578) + 36.9659(0.2422) =
= 26.4993 + 8.9531 = 35.4524 amu
Thus, the term “ average atomic mass “ is a <u>weighted</u> average so it is calculated differently from a normal average
Given :
Compound A reacts with Compound B to form only one product, Compound C.
The usual percent yield of C in this reaction is 40%.
10.0 g of A are reacted with excess Compound B, and 6.4 g of Compound C
To Find :
The theoretical yield of C.
Solution :
We know, % yield is given by :

Putting given values , we get :

Therefore, theoretical yield of C is 16 g.
Hence, this is the required solution.