Question

How many moles of dipyrithione contain 6.3×1024  atoms of nitrogen?

Answer 1

Answer:

5.23 moles of C₁₀H₈N₂O₂S₂

Explanation:

In order to find the moles of dipyrithione we need to know its formula:

C₁₀H₈N₂O₂S₂

1 mol of N contains 6.02×10²³ atoms

We need to find out the moles of 6.3×10²⁴ atoms of N

6.3×10²⁴ atoms . 1 mol /6.02×10²³ atoms = 10.4 moles of N

Therefore, we know that 1 mol of dipyrithione has 2 moles of N, so we need to make this rule of three:

2 moles of N are contained in 1 mol of C₁₀H₈N₂O₂S₂

10.4 moles of N must be contained in (10.4 . 1) /2 = 5.23 moles of C₁₀H₈N₂O₂S₂

Answer 2

Answer:

5.2 moles dipyrithione contain 6.3 * 10^24 atoms of nitrogen

Explanation:

Step 1: Data given

Dipyrithione = C10H8N2O2S2

Number of Avogadro = 6.02 * 10^23

Number of nitrogen atoms = 6.3 * 10^24 atoms

Step 2: Calculate moles nitrogen

Moles nitrogen = atoms nitrogen / number of Avogadro

Moles nitrogen = 6.3 * 10^24 / 6.02 * 10^23

Moles nitrogen = 10.47 moles

Step 3: Calculate moles dipyrithione

In 1 mol dipyrithione we 2 moles N

For 10.47 moles N we have 10.47/2 = 5.2 moles dipyrithione

5.2 moles dipyrithione contain 6.3 * 10^24 atoms of nitrogen