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3 years ago

12

Have you ever had a dream that, that, um, that you had, uh, that you had to, you could, you do, you wit, you wa, you could do so

, you do you could, you want, you wanted him to do you so much you could do anything?

2 answers:

Ivenika [448]3 years ago

4 0

DNDUDHHDHEUDIEIDID DUDE

Murljashka [212]3 years ago

3 0

Answer:

I love that video it’s so funny!!!

Explanation:

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Fig.3 shows three 10 g particles that have been glued to a rod of length L = 6 cm and negligible mass. The assembly can rotate a

Phoenix [80]

(a) The amount of work required to change the rotational rate is 0.0112 J.

(b) The decrease in the rotational inertia when the outermost particle is removed is 64.29%.

<h3>Moment of inertia of the rod</h3>

The moment of inertia of the rod from the axis of rotation is calculated as follows;

I = md² + m(2d)² + m(3d)²

where;

m is mass = 10 g = 0.01 kg
d = 3 equal division of the length

d = 6/3 = 2 cm = 0.02 m

I = md²(1 + 2² + 3²)

I = 14md²

I = 14(0.01)(0.02)²

I = 5.6 x 10⁻⁵ kg/m³

<h3>Work done to change the rotational rate</h3>

K.E = ¹/₂Iω²

K.E = ¹/₂(5.6 x 10⁻⁵)(60 - 40)²

K.E = ¹/₂(5.6 x 10⁻⁵)(20)²

K.E = 0.0112 J

<h3>Percentage decrease of rotational inertia when the outermost particle is removed</h3>

I₂ = md² + m(2d)²

I₂ = 5md²

ΔI = 14md² - 5md²

ΔI = 9md²

η = (ΔI/I) x 100%

η = (9md²/14md²) x 100%

η = 64.29 %

Learn more about rotational inertia here: brainly.com/question/14001220

#SPJ1

4 0

1 year ago

Softa [21]

Answer:

5N as it causes th ball to move

4 0

2 years ago

The specific heat of liquid water is 4.184 j/g-k. the latent heat of melting (ice to liquid is 6.0102 kj/mol. define q100-0= the

Shalnov [3]

Q100 -q100-o=111111111

4 0

3 years ago

The former soviet union launched the first artificial earth satellite. What is the name of this satelitte?

faltersainse [42]

Answer:

Sputnik I.

Explanation:

The Soviet Union (former) launched the first artificial earth satellite called Sputnik I on October 4, 1957.

It had a diameter of 58 cm and it weighed 83.6 kg. It had an orbital period of 5880 seconds around the earth. It orbited the 11 weeks (officially 3 weeks but then, its battery died and it orbited for 8 weeks before falling back into the earth's atmosphere).

7 0

3 years ago

The heater element of a particular 120-V toaster is a 8.9-m length of nichrome wire, whose diameter is 0.86 mm. The resistivity

AleksAgata [21]

Answer:

Power, P = 722.96 watts

Explanation:

It is given that,

Voltage, V = 120 V

Length of nichrome wire, l = 8.9 m

Diameter of wire, d = 0.86 mm

Radius of wire, r = 0.43 mm = 0.00043 m

Resistivity of wire, $\rho=1.3\times 10^{-6}\ \Omega-m$

We need to find the power drawn by this heater. Power is given by :

$P=\dfrac{V^2}{R}$

And, $R=\rho\dfrac{l}{A}$

$P=\dfrac{V^2\times A}{\rho\times l}$

$P=\dfrac{120^2\times \pi (0.00043)^2}{1.3\times 10^{-6}\times 8.9}$

P = 722.96 watts

So, the power drawn by this heater element is 722.96 watts. Hence, this is the required solution.

3 0

3 years ago