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2 years ago

When liquid bromine is cooled to form a solid, which of the following types of solid would it form?.

Chemistry

1 answer:

Diano4ka-milaya [45]2 years ago

8 0

Answer:

If liquid bromine is cooled to form a solid, which type of solid does it form? Brass is made by melting copper and zinc and physically mixing them. As this alloy is cooled, it forms a solid where the copper and zinc are not chemically bonded together.

Explanation:

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Calculate mass in grams in 2.28 mol of h2so4

Nezavi [6.7K]

223.44 grams is the answer. Multiply 2.28 times the gram formula mass of h2so4

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3 years ago

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How many grams of O2(g) are needed to completely burn 46.0 g C3H8(g)?

Veronika [31]

Answer:

167,3 grams of O2 (g)

Explanation:

According to the following balanced equation:

C3H8 + 5 02 ---> 3 CO2 + 4 H20

We calculate the mass of the moles:

5 mol O2 = 16grams/mol x2x 5= 160 grams/mol

1 mol C3H8= 3 x12 grams/mol + 8 x 1 gram/mol= 44 grams/mol

If 44 grams C3H8 react with--------- 160 grams O2

46 gramsC3H8 react with --------X = (46x160)/44 =167, 3 grams O2

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4 years ago

Use complete sentences to differentiate between acids and bases on the basis of touch. Give an example of each type.

stellarik [79]

<h2>Answer:</h2>

Acids are sour, gives burning sensation, generally sticky, reacts with metals to produce hydrogen gas.

example: Acetic acid

Bases are opposite as they are bitter, generally odorless (except ammonia), they are slippery;

example: sodium bicarbonate

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3 years ago

Which of the following is not a class of clouds?

cricket20 [7]

A. Intermediate is the answer

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4 years ago

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How many moles would you need to have 7.85 x 10^22 molecules of ammonia (NH3).

RSB [31]

<h3>Answer:</h3>

0.130 moles NH₃

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 7.85 × 10²² molecules NH₃

[Solve] moles NH₃

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

[DA] Set up: $\displaystyle 7.85 \cdot 10^{22} \ molecules \ NH_3(\frac{1 \ mol \ NH_3}{6.022 \cdot 10^{23} \ molecules \ NH_3})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 0.130355 \ moles \ NH_3$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

0.130355 moles NH₃ ≈ 0.130 moles NH₃

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3 years ago