Answer:
We can see that at the boiling point, both liquid and gas are in equilibrium with one another. This is true for any applied pressure and boiling point temperature combination. As a result, we see liquid-gas equilibrium for every temperature and pressure combination on the graph in Figure 13.6.
Answer: metabolic acidosis.
Explanation:
Anion Gap(AG) is the difference between positively charged ions and negatively charged ions. It is usually expressed in milliequivalents per litre of millimoles per litres.
Anion Gap is measured or calculated when there is a need to know the cause of metabolic acidosis. To
Anion Gap can be calculated with or without potassium.
(1). With potassium= ([Na^+] + [K^+]) − ([Cl^−] + [HCO^−3]).
From the question; client's lab values are sodium 166 mEq/L, potassium 5.0 mEq/L, chloride 115 mEq/L, and bicarbonate 35 mEq/L.
Slotting in the values, we have;
==>[ (166+5) - (115+35)] mEq/L.
(2). Without potassium:
==> [Na^+] - ([Cl^−] + [HCO^−3]).
==> [(166) - 115 + (35)] mEq/L
Normal Anion gap is 20 mEq/L(Calculating with Potassium) and 8-16 mEq/L (calculating without potassium).
5000L • 1 mole /22.4L so approximately 223 moles
Answer:
1.) Single Displacement Reaction
2.) Synthesis Reaction
3.) Single Displacement Reaction
4.) Decomposition Reaction
5.) Double Displacement Reaction
Explanation:
Single Displacement Reaction: a reaction in which an element is swapped out for another in a molecule
Double Displacement Reaction: a reaction in which the cation of one molecule is swapped out with the cation of another
Decomposition Reaction: a reaction in which a molecule breaks down into smaller molecules/atoms
Synthesis Reaction: a reaction in which atoms or molecules come together to create a larger molecule
The correct answer for the given question above would be option B. HYDROGEN. The form that has the greatest number of <span>strong covalent bonds and is therefore the backbone of organic molecules including carbohydrates, proteins, lipids and nucleic acids is HYDROGEN. Hope this answers your question.</span>