Answer and Explanation:
- <em>Computers ( The computers are very old and very slow, and we have to notice that almost everyone are using computers at the same time at the school, which makes it even harder for it to load up assignments. )</em>
- <em>The Rick Rolling ( Everyone keeps sending links to teachers and students saying that it is part of some assignment but then you have to listen to Rick Astley, they should really block these links. )</em>
- <em>The lockers ( The lockers are also very old and they are breaking down and rusting a lot from the moisture in the hallways. One of the lockers even broke down today!!! I hope they can fix this so no one else gets hit with a locker door. )</em>
<em>Hope this helps! ;)</em>
Answer:
The answer is
<h2>6.54 mL</h2>
Explanation:
The volume of a substance when given the density and mass can be found by using the formula

From the question
mass of ball = 8.5 g
density = 1.3 g/mL
It's volume is

We have the final answer as
<h3>6.54 mL</h3>
Hope this helps you
The correct answer is <span>D) centrifuge the mixture because the substance with the highter density will be pulled to the bottom
When things spin around, like a centrifuge, the centripetal force draws things towards the middle. If you make it a bit like a spiral and put it sideways, then the denser thing will go to the bottom while the less dense ones will remain on the outside. </span>
Answer:
Volume = 35.2×220×6.0 = 46464 centimeters³
Explanation:
Answer : The mass of helium gas added must be 12.48 grams.
Explanation : Given,
Mass of helium (He) gas = 6.24 g
Molar mass of helium = 4 g/mole
First we have to calculate the moles of helium gas.

Now we have to calculate the moles of helium gas at doubled volume.
According to the Avogadro's law, the volume of gas is directly proportional to the number of moles of gas at same pressure and temperature. That means,

or,

where,
= initial volume of gas = V
= final volume of gas = 2V
= initial moles of gas = 1.56 mole
= final moles of gas = ?
Now we put all the given values in this formula, we get


Now we have to calculate the mass of helium gas at doubled volume.


Therefore, the mass of helium gas added must be 12.48 grams.