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Vinil7 [7]
3 years ago
11

4 kg

Physics
1 answer:
nirvana33 [79]3 years ago
3 0

Answer:

E = 62.72 J

Explanation:

Given that,

The mass of a ball, m = 4 kg

The teacher raised the lawn bowling ball to a height of 1.6 meters before they released it.

We need to find the gravitational potential energy of the ball.

We know that,

E = mgh

Where

g is acceleration due to gravity

So,

E = 4 kg × 9.8 m/s² × 1.6 m

E = 62.72 J

So, the gravitational potential energy of the ball is equal to 62.72 J.

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Which sentence in the passage can be used to conclude that Eris is a dwarf planet and not a planet?
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Eris is slightly more massive than Pluto. However, both of them are smaller than Earth's Moon.
This should conclude that Eris is a dwarf planet.
3 0
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Some one help my science homework is due tomorrow and I'm so stuck with question 8-9, and 11-12
yuradex [85]
Off the top of my head, I only know 9 and 11, so I'll answer those two.

9) A heterotroph is an organism that relies on other organisms for food/energy
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5 0
3 years ago
A bulb converts 9J of energy in each second from an input of 100J of energy. Calculate efficiency of this light bulb
77julia77 [94]
Efficiency is calculated through dividing the actual mechanical advantage by the hypothetical mechanical advantage:

- the actual mechanical advantage is 9J because that's how much work the light bulb doing

- the hypo. mechanical advantage is 100J. Ideally, in a perfect world, the light bulb can convert 100J input into 100J output, but do to resistance and other factors it is not possible.

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8 0
3 years ago
What is the resistance of : A) A 1.70 m long copper wire that is 0.700 mm in diameter? B) A 20.0 cm long piece of carbon with a
astra-53 [7]

Answer:

(I). The resistance of the copper wire is 0.0742 Ω.

(II). The resistance of the carbon piece is 1.75 Ω.

Explanation:

Given that,

Length of copper wire = 1.70 m

Diameter = 0.700 mm

Length of carbon piece = 20.0 cm

Cross section areaA = (2.00\times10^{-3})^2\ m

(I). We need to calculate the area of copper wire

Using formula of area

A=\pi r^2

A=3.14\times(\dfrac{0.700\times10^{-3}}{2})^2

We need to calculate the resistance

Using formula of resistance

R=\dfrac{\rho l}{A}

Put the value into the formula

R=\dfrac{1.68\times10^{-8}\times1.70}{3.14\times(\dfrac{0.700\times10^{-3}}{2})^2}

R=0.0742\ \Omega

(II). We need to calculate the resistance

Using formula of resistance

R=\dfrac{\rho l}{A}

Put the value into the formula

R=\dfrac{3.5\times10^{-5}\times20\times10^{-2}}{(2.00\times10^{-3})^2}

R=1.75\ \Omega

Hence, (I). The resistance of the copper wire is 0.0742 Ω.

(II). The resistance of the carbon piece is 1.75 Ω.

8 0
3 years ago
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Work = force x distance
= 100N (force) x 0.5m (distance)
=  50J
4 0
3 years ago
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