The vehicle accelerates at 2.648 m/s².
We have:
Initial velocity, u = 50 miles per hour = 22.352 m/s
final velocity, v = 80 miles per hour = 35.762 m/s
Time, t = 5 seconds
The time in hours is:
t = 5 seconds
Now, the acceleration of the car can be calculated using the formula:
v = u + at
35.762 = 22.352 + a(5)
a(5) = 30
a = 2.682 m/s²
From the calculations above, the acceleration of the car is 2.682 m/s².
Ler more about acceleration here:
brainly.com/question/605631
#SPJ9
R = 2700 ohm
I = 2.4 mA = 2.4 × 10^(-3) A
I = Q/t
Q = I × t = 2.4 × 10^(-3) × 15 s = 36 C
Given :
A mover slides a refrigerator weighing 650 N at a constant velocity across the floor a distance of 8.1 m.
The force of friction between the refrigerator and the floor is 230 N.
To Find :
How much work has been performed by the mover on the refrigerator.
Solution :
Since, refrigerator is moving with constant velocity.
So, force applied by the mover is also 230 N ( equal to force of friction ).
Now, work done in order to move the refrigerator is :

Hence, this is the required solution.
Answer:
a) a = 3.29 m/s²
b) a = 3.51 m/s²
Explanation:
mass of dogs = 19 kg
loaded sled mass = 210 Kg
a)writing all the forces in x direction

a = 3.29 m/s²
b) acceleration when sled start to move the friction will now be acting will be kinetic friction.

a = 3.51 m/s²
You would be in an editing mode when you can see a blinking insertion point on a field. In addition, in any word processing software, it would basically signify that you can already type on the document. Another name for the insertion point would be the I-beam as displayed on the screen.