Answer:
The definition of that same given problem is outlined in the following section on the clarification.
Explanation:
The Q seems to be endless (hardly any R on the circuit). So energy equations to describe and forth through the inducer as well as the condenser.
Presently take a gander at the energy stored in your condensers while charging is Q.
⇒ 
So conclude C doesn't change substantially as well as,
When,
⇒ 
⇒ 
And therefore only half of the population power generation remains in the condenser that tends to leave this same inductor energy at 3/4 U.
19.6 N........weight is equal to mass multiplied by gravitational force which is 9.8 m/s2......2 x 9.8 gives 19.6 N
Answer is E I’m pretty sure
Answer:
heat
Explanation:
because heat the other of transferring energy