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Fed [463]
1 year ago
15

What is the molar absorptivity () of benzoic acid at 228 nm? assume that the path length is 1. 00 cm

Chemistry
1 answer:
Grace [21]1 year ago
8 0

The molar absorptivity () of benzoic acid at 228 nm? assume that the path length is 1. 00 cm is = 11178 M-1. cm-1

We are given, absorbance spectrum and from that the absorbance of benzoic acid at 228 nm

Absorbance = 0.8

Now we need to calculate the molar absorptivity of benzoic acid at 228 nm

We know at the 228 nm the A = 0.8 and C = 8.74 mg/L.

We also given the l = 1 cm

Moles of benzoic acid = 0.00874 g / 122.12 g.mol-1

                                  = 7.16*10-5 moles

So, C of benzoic acid = 7.16*10-5 moles / L

We know the

ε = A/C*l

 = 0.80 / 7.16*10-5 M. 1 cm

 = 11178 M-1. cm-1

Learn more about  molar absorptivity here:-brainly.com/question/13350541

#SPJ4

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Calculate the number of grams of Fe that are produced when 57 grams of FeO is reacted with excess aluminum in the following reac
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Answer:

Mass of Fe produced = 44.7 g

Explanation:

Given data:

Mass of Fe produced in gram = ?

Mass of FeO react = 57 g

Solution:

Chemical equation:

2Al + 3FeO  →  3Fe + Al₂O₃

Number of moles of FeO:

Number of moles = mass/ molar mass

Number of moles = 57 g/ 71.844 g/mol

Number of moles = 0.8 mol

Now we will compare the moles of Fe with FeO from balance chemical equation.

                    FeO          :          Fe

                       3            :           3

                    0.8            :          0.8

Mass of Fe:

Mass = Mass × molar mass

Mass = 0.8 mol ×  55.845 g/mol

Mass = 44.7 g

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3 years ago
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meriva
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Now they feel it is best to have you identify an unknown gas based on its properties. Suppose 0.508 g of a gas occupies a volume
pishuonlain [190]

Answer: Option (b) is the correct answer.

Explanation:

The given data is as follows.

             mass = 0.508 g,               Volume = 0.175 L

             Temperature = (25 + 273) K = 298 K,       P = 1 atm

As per the ideal gas law, PV = nRT.

where,  n = no. of moles = \frac{mass}{\text{molar mass}}

Hence, putting all the given values into the ideal gas equation as follows.

               PV = \frac{mass}{\text{molar mass}} \times RT            

           1 atm \times 0.175 L = \frac{0.508 g}{\text{molar mass}} \times 0.0821 L atm/ K mol \times 298 K  

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As the molar mass of a chlorine atom is 35.4 g/mol and it exists as a gas. So, molar mass of Cl_{2} is 70.8 g/mol or 71 g/mol (approx).

Thus, we can conclude that the gas is most likely chlorine.

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3 years ago
Explain vapour pressure and surface tension What is plasma
worty [1.4K]

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Surface Tension: is the attraction between liquid molecules.

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Answer:

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