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2 years ago

Help me pls im terrible at physics

Physics

1 answer:

Tatiana [17]2 years ago

3 0

Answer:

There is a single pathway for charge flow in the circuit.

Explanation:

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A child attaches a rubber ball to a string and whirls it around in a circle overhead. If the string is 0.2m long and the ball's

AlladinOne [14]

Answer:

The centripetal acceleration, $a_c = 1280 m/s^2$

Explanation:

Centripetal acceleration is given by the formula:

$a_c = \frac{v^2}{r}$

Where the speed of the ball, v = 16 m/s

Length of the string, r = 0.2 m

Substituting these parameters into the centripetal equation above:

$a_c = \frac{16^2}{0.2}\\a_c = \frac{256}{0.2}\\a_c = 1280 m/s^2$

4 0

3 years ago

Use the periodic table to complete this equation that represents the process of nuclear fusion.

yanalaym [24]

Answer:

7 N 14 + 1 H 1 --> 8 O 15

Explanation:

Hope this answers your question.

8 0

3 years ago

Read 3 more answers

Suppose a car is traveling at +25.0 m/s, and the driver sees a traffic light turn red. After 0.340 s has elapsed (the reaction t

scoundrel [369]

First, we will get the distance traveled before the driver applied the brakes.
distance = velocity * time
distance = 25*0.34 = 8.5 m

Now, we will calculated the distance that the car traveled after the driver applied the brakes. To do this, we will use the equation of motion:
vf^2 = vi^2 + 2*a*d where:
vf = zero, vi = 25 m/s and a = -7 m/s^2
Note: The negative sign is only to show deceleration
d = 1/2*(625) /(7) = 44.6428 m

The total stopping distance = 8.5 + 44.6428 = 53.1428 m

3 0

3 years ago

Find the energy released when there is a decrease of 0.3kg of material in a nuclear reaction

MrRissso [65]

Answer:

E = 2.7 x 10¹⁶ J

Explanation:

The release of energy associated with the mass can be calculated by Einstein's mass-energy relation, as follows:

$E = mc^2$

where,

E = Energy Released = ?

m = mass of material reduced = 0.3 kg

c = speed of light = 3 x 10⁸ m/s

Therefore,

$E = (0.3\ kg)(3\ x\ 10^8\ m/s)^2$

E = 2.7 x 10¹⁶ J

4 0

2 years ago

Four seconds after being launched, what is the height of a ball that starts from a height of 12 m with an initial upward velocit

MrMuchimi

Answer:

15.24 m/s in the downward direction

Explanation:

Given that the initial upward velocity of the ball is 24 m/s.

Assuming that the upward direction is positive.

As gravitational force acts in the downward direction and the direction of acceleration is the same as the direction of force, so the acceleration due to gravity will be negative.

Now, from the equation of motion, when an object is launched with initial velocity u, the final velocity, v, of an object after time t is v=u+at.

Given that u=24 m/s, t=4 seconds, $g=-9.81 m/s^2$ .

So, the final velocity is

$v= 24 + (-9.81)\times 4 \\\\\Rightarrow v= 24-9.81\times 4$

$\Rightarrow v=-15.24$ m/s

Here, the negative sign means the final velocity is in the downward direction.

Hence, the velocity after 4 seconds is 15.24 m/s in the downward direction.

8 0

3 years ago