Help me pls im terrible at physics
1 answer:
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Answer:
(a) With a short line, the A,B,C,D parameters are:
A = 1pu B = 1.685∠60.8°Ω C = 0 S D = 1 pu
(b) The sending-end voltage for 0.9 lagging power factor is 35.96
(c) The sending-end voltage for 0.9 leading power factor is 33.40
Explanation:
(a)
Considering the short transition line diagram.
Apply kirchoff's voltage law to the short transmission line.
Write the equation showing the relations between the sending end and the receiving end quantities.
Compare the line equations with the A,B,C,D parameter equations.
(b)
Determine the receiving-end current for 0.9 lagging power factor.
Determine the line-to-neutral receiving end voltage.
Determine the sending end voltage of the short transition line.
Determine the line-to-line sending end voltage which is the sending end voltage.
(c)
Determine the receiving-end current for 0.9 leading power factor.
Determine the sending-end voltage of the short transition line.
Determine the line-to-line sending end voltage which is the sending end voltage.
Answer:
The total distance is 280 [m]
Explanation:
In order to solve this problem we must use the expressions of kinematics. The clue to solve this problem is that the motorcyclist starts from rest, i.e. its initial speed is zero.
where:
Vf = final velocity [m/s]
Vo = initial velocity = 0
a = acceleration = 2 [m/s²]
t = time = 12 [s]
Vf = 0 + (2*12)
Vf = 24 [m/s]
With this velocity, we can calculate the displacement using the following expression.
where
x = distance traveled [m]
24² = 0 + (2*2*x)
x = 576/(4)
x = 144 [m]
Note: The positive sign in the equations is because the car is accelerating, it means its velocity is increasing.
The other important clue to solve this problem in the second part is that the final velocity is now the initial velocity.
We must calculate the final velocity.
Vf = final velocity [m/s]
Vi = initial velocity = 24 [m/s]
a = desacceleration = 5 [m/s²]
t = time = 4 [s]
Vf = 24 + (4*5)
Vf = 44 [m/s]
With this velocity, we can calculate the displacement using the following expression.
where
x = distance traveled [m]
44² = 24² + (2*5*x)
x = 1360/(10)
x = 136 [m]
Note: The positive sign in the equations is because the car is accelerating, it means its velocity is increasing.
Therefore the total distance is Xt = 144 + 136 = 280 [m]