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kati45 [8]
3 years ago
10

How long does it take electrons to get from a car battery to the starting motor? Assume the current is 300 A and the electrons t

ravel through a copper wire with cross-sectional area 0.21 cm2 and length 0.85 m.The number of charge carriers per unit volume is 8.49 1028 m3.
Engineering
1 answer:
yuradex [85]3 years ago
6 0

Answer:

t=13.49 min

Explanation:

Given that

I=300 A

A= 0.21 cm²

L= 0.85 m

Number of charge carriers per unit volume = 8.49 x 10²⁸ m⁻³.

We know speed of the electron given as

V=J/ne

J= I/A

So

V=I/neA

V=\dfrac{300}{8.49\times 10^{28}\times 1.6\times 10^{-19}\times 0.21\times 10^{-4} }

V=0.00105 m/s

lets take t is the time when electron travels from car battery to the starting motor

t = L/V

t=\dfrac{0.85}{0.00105}

t=809.52 s

t=13.49 min

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An open vat in a food processing plant contains 500 L of water at 20°C and atmospheric pressure. If the water is heated to 80°C,
tester [92]

Answer:

percentage change in volume is 2.60%

water level rise is 4.138 mm

Explanation:

given data

volume of water V = 500 L

temperature T1 = 20°C

temperature T2 = 80°C

vat diameter = 2 m

to find out

percentage change in volume and how much water level rise

solution

we will apply here bulk modulus equation that is ratio of change in pressure   to rate of change of volume to change of pressure

and we know that is also in term of change in density also

so

E = -\frac{dp}{dV/V}  ................1

And -\frac{dV}{V} = \frac{d\rho}{\rho}   ............2

here ρ is density

and we know ρ  for 20°C = 998 kg/m³

and ρ  for 80°C = 972 kg/m³

so from equation 2 put all value

-\frac{dV}{V} = \frac{d\rho}{\rho}

-\frac{dV}{500*10^{-3} } = \frac{972-998}{998}

dV = 0.0130 m³

so now  % change in volume will be

dV % = -\frac{dV}{V}  × 100

dV % = -\frac{0.0130}{500*10^{-3} }  × 100

dV % = 2.60 %

so percentage change in volume is 2.60%

and

initial volume v1 = \frac{\pi }{4} *d^2*l(i)    ................3

final volume v2 = \frac{\pi }{4} *d^2*l(f)    ................4

now from equation 3 and 4 , subtract v1 by v2

v2 - v1 =  \frac{\pi }{4} *d^2*(l(f)-l(i))

dV = \frac{\pi }{4} *d^2*dl

put here all value

0.0130 = \frac{\pi }{4} *2^2*dl

dl = 0.004138 m

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8 0
2 years ago
Two variables, num_boys and num_girls, hold the number of boys and girls that have registered for an elementary school. The vari
Flauer [41]

Answer:

Using python

num_boys = int(input("Enter number of boys :"))

num_girls = int(input("Enter number of girls :"))

budget = int(input("Enter the number of dollars spent per school year :"))

try:

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3 0
3 years ago
weight of 1000 pounds is suspended from two cables. The allowable stress in the cables is 1500 psi. Find the minimum diameter fo
kari74 [83]

Answer:

The minimum diameter for each cable should be 0.65 inches.

Explanation:

Since, the load is supported by two ropes and the allowable stress in each rope is 1500 psi. Therefore,

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Here,

Weight = 1000 lb

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where, r = minimum radius for each cable

(1/2)(1000 lb/πr²) = 1500 psi

500 lb/1500π psi = r²

r = √1.061 in²

r = 0.325 in

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Diameter = 2(radius) = 2r

Diameter = 2(0.325 in)

<u>Diameter = 0.65 in</u>

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vfiekz [6]

Answer:

C. underground road

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