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Juliette [100K]
3 years ago
14

A school has 8 period in a day such the each periods is of 35 minutes.lf the number of period is reduced to 7, then how long wou

ld each period be?​
Chemistry
1 answer:
scZoUnD [109]3 years ago
5 0

Answer:

45 minutes about

Explanation:

i think because i have 7 periods with 45 minutes each

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Como clasificarias la máquina de la siguiente ilustración? tijera​
Lina20 [59]

Answer:

<u><em></em></u>

  • <u><em>máquina simple: palanca</em></u>

Explanation:

En vista de que  la pregunta está realizada en español, la respuesta la doy en el mismo lenguage.

La<em> palanca</em> es una máquina simple que consiste en una barra rígida que puede girar alrededor the un punto the pivote.

La forma en que functiona una palanca es que se aplica la ferza en el extremo de la barra que está más alejado del pivote. Este extremo puede desplazarse una larga distancia o arco, con una fuerza pequeña, haciendo que los puntos que están al otro lado del pivote, a una menor distancia de este, se desplacen una distancia o arco menor pero con más fuerza que la aplicada.

6 0
4 years ago
The electron configuration for aluminum (Al) is shown below:
Serjik [45]

Answer:

It is the third choice

Explanation:

Just did assignment

3 0
4 years ago
ANSWER FAST PLZZZ!!!!!!!!!!!!!
goldfiish [28.3K]

Answer:

1 and 2

Explanation:

1 is negative

2 is negative

3 is positive

5 0
4 years ago
What is the concentration of no3- ions in a solution prepared by dissolving 15.0 g of ca(no3)2 in enough water to produce 300. m
r-ruslan [8.4K]

Ca(NO3)2 -------> Ca²⁺ +2NO3⁻

M(Ca(NO3)2)= M(Ca) + M(N) + 6M(O)= 40.0 +14.0 +6*16.0 = 150 g/mol

15.0 g Ca(NO3)2 * 1mol/150 g = 0. 100 mol Ca(NO3)2


Ca(NO3)2 -------> Ca²⁺ +2NO3⁻
1 mol                               2 mol
0.100 mol                           0.200 mol

We have 0.2 mol NO3⁻ in 300. mL=0.300 L of solution,
so
0.200 mol NO3⁻ / 0.300 L solution ≈ 0.667 mol NO3⁻ /L solution = 0.667 M

Concentration of NO3⁻ is 0.667 M.



4 0
3 years ago
7. Write a formula for each of the following:
sergeinik [125]

Answer : The formula for each of the following is:

(a) C_{22}H_{46}

(b) C_{17}H_{34}

(c) C_{13}H_{24}

Explanation :

  • Alkanes are hydrocarbon in which the carbon atoms are connected with single covalent bonds.

The general formula of alkanes is C_n H_{2n+2} where n is the number of the carbon atoms present in a molecule of alkane.

  • Alkenes are hydrocarbon in which the carbon atoms are connected with double covalent bonds.

The general formula of alkenes is C_n H_{2n} where n is the number of the carbon atoms present in a molecule of alkene.

  • Alkynes are hydrocarbon in which the carbon atoms are connected with triple covalent bonds.

The general formula of alkynes is C_n H_{2n-2} where n is the number of the carbon atoms present in a molecule of alkyne.

(a) An alkane with 22 carbon atoms

Putting n = 22 in the general formula of alkane, we get the formula of alkane as, C_{22}H_{2(22)+2} or C_{22}H_{46}

(b) An alkene with 17 carbon atoms

Putting n = 17 in the general formula of alkene, we get the formula of alkene as, C_{17}H_{2(17)} or C_{17}H_{34}

(c) An alkyne with 13 carbon atoms

Putting n = 13 in the general formula of alkyne, we get the formula of alkyne as, C_{13}H_{2(13)-2} or C_{13}H_{24}

3 0
3 years ago
Read 2 more answers
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