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3 years ago

Electrons will fill all empty orbitals within a sublevel before they begin to pair up. This is:

Chemistry

2 answers:

disa [49]3 years ago

8 0

The answer is A. Hund’s rule

seraphim [82]3 years ago

5 0

Answer: Hund’s rule

Explanation:

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Heat is transferred directly from a heat reservoir at 200 C to another heat reservoir at 5C. If the amount of heat transferred i

Daniel [21]

Answer:

ΔS=0.148 KJ/K

Explanation:

Given that

Q = 100 KJ

T₁=200°C

T₁=200+273 = 437 K

T₂=5°C

T₂=5 + 273 = 278 K

Reservoir 1 is rejecting heat that is why it taken as negative while the reservoir 2 is gaining the heat that is why it is taken as positive.

So the total change in entropy given as

ΔS= - Q/T₁ + Q/T₂

ΔS= - 100/473 + 100/278 KJ/K

ΔS=0.148 KJ/K

4 0

3 years ago

How long would it take to produce enough aluminum to make a case (24 cans) of aluminum soft drink cans if each can used 3 g of a

kozerog [31]

Answer : It takes time to produce 3 g of aluminium is, 165 seconds.

Explanation :

As we are given that the mass of aluminium is, 3 grams. Now we have to calculate the total mass of aluminum.

Total mass of aluminum = 3g × 24 = 72 g

Now we have to calculate the moles of aluminum.

$\text{Moles of Al}=\frac{\text{Mass of Al}}{\text{Molar mass of Al}}$

Molar mass of Al = 27 g/mol

$\text{Moles of Al}=\frac{72g}{27g/mol}=2.67mol$

As, 1 mole of Al has 3 Faradays

So, 2.67 mole of Al has = $2.67\times 3=80.1$ Faradays

and,

Charge = $80.1\text{ Faradays}\times \frac{96500\text{ coulombs}}{1\text{ Faradays}}=7.73\times 10^6\text{ coulombs}$

Current = $5.00\times 10^4A\times \frac{93.9}{100}=46950A$

Now we have to calculate the time.

$Time=\frac{Charge}{Current}=\frac{7.73\times 10^6}{46950}=164.6s\aaprox 165s$

Hence, it takes time to produce 3 g of aluminium is, 165 seconds.

5 0

3 years ago

We would expect warmer Northern Atlantic currents to have all BUT ONE of these consequences on Earth.

Liula [17]

its C) decreased precipitation

7 0

3 years ago

Read 2 more answers

A compound is made of 6.00 grams of oxygen, 7.00 grams of nitrogen, and 20.00grams of hydrogen. Find the percent composition of

xxTIMURxx [149]

The percent composition of the compound.

A O-18.18%, N-21.21%, H-60.60%

<h3>Further explanation</h3>

Given

6.00 grams of oxygen,

7.00 grams of nitrogen,

20.00 grams of hydrogen.

Required

The percent composition

Solution

Total mass :

= mass of O + mass of N + mass of H

= 6 + 7 + 20

= 33 g

% O = 6/33 x 100%= 18.18%

% N = 7/33 x 100%=21.21%

% H = 20/33 x 100% = 60.6 %

6 0

2 years ago

Indicate the hybridization of the central atom in (a) BCl3, (b) AlCl4-, (c) CS2, (d) GeH4

Tamiku [17]

Explanation:

(a) BCl3= sp² hybridization

(b) AlCl4- = sp³ hybridization

(d) GeH4 = sp³ hybridization

5 0

3 years ago