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dedylja [7]
3 years ago
8

Make v the subject of the relation f=vu/v+u​

Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
8 0

Answer:

v=fu/u-f

Step-by-step explanation:

the answer is explained in the diagram

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Decide whether y is a function of x.<br> y=-3x-4
Nataly [62]
Yes, for every value of x, there is only one value of y. This means that y is a function of x.
4 0
3 years ago
Write a system of equations to describe the situation below, solve using elimination, and fill in the blanks. At a historical la
Alborosie

Answer:

The number of candles will hold 2 candles

And large candle holder will hold 6 candles.

Step-by-step explanation:

Let the number of candles  small candle holder have x

And the number of candles large candle holder have y

So, according to the information given in the question:

17 small candle holders means 17 x

and 2 large candle holders means 2y

using a total of 46 candles means 17x+2y=46     (1)

Similarly, 8 small candle holders and 2 large candle holders, for a total of 28 candles gives:

8x+2y=28      (2)

We will solve equation (1) and (2) by elimination method:

Subtractijng the two equations we get:

9x=18

\Rightarrow x=2

Substitute x=2 in equation(2) we get:8(2)+2y=28

2y=12

\Rightarrow y=6

So, the number of candles will hold 2 candles

And large candle holder will hold 6 candles.

7 0
3 years ago
Which algebraic expression means “four less than three times a number”?
Yuliya22 [10]

Answer:

3 n minus 4 represents the expression "four less than three times a number"

3 0
3 years ago
Read 2 more answers
The points A(1, 4), B(5,1) lie on a circle. The line segment AB is a chord. Find the equation of a diameter of the circle.
tangare [24]

Check the picture below.

well, we want only the equation of the diametrical line, now, the diameter can touch the chord at any several angles, as well at a right-angle.

bearing in mind that <u>perpendicular lines have negative reciprocal</u> slopes, hmm let's find firstly the slope of AB, and the negative reciprocal of that will be the slope of the diameter, that is passing through the midpoint of AB.

\bf A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{1}}}\implies \cfrac{-3}{4} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{slope of AB}}{-\cfrac{3}{4}}\qquad \qquad \qquad \stackrel{\textit{\underline{negative reciprocal} and slope of the diameter}}{\cfrac{4}{3}}

so, it passes through the midpoint of AB,

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{5+1}{2}~~,~~\cfrac{1+4}{2} \right)\implies \left(3~~,~~\cfrac{5}{2} \right)

so, we're really looking for the equation of a line whose slope is 4/3 and runs through (3 , 5/2)

\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{\frac{5}{2}}) \stackrel{slope}{m}\implies \cfrac{4}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{\cfrac{5}{2}}=\stackrel{m}{\cfrac{4}{3}}(x-\stackrel{x_1}{3})\implies y-\cfrac{5}{2}=\cfrac{4}{3}x-4 \\\\\\ y=\cfrac{4}{3}x-4+\cfrac{5}{2}\implies y=\cfrac{4}{3}x-\cfrac{3}{2}

4 0
3 years ago
Loan A (bank) requires a total payback of $54,289.44 while Loan B (dealership) requires a total payback of $55,098.60.
dedylja [7]

Answer: Loan B requires more interest by $809.16.

Step-by-step explanation:

Subtract the total pay back of loan B from loan A

= $55,098.60 - $54,289.44

= $809.16

I hope this helps, please mark as brainliest answer.

8 0
3 years ago
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