You can put a known amount sodium into some sort of time release mechanism such as a pill made from soluble material. Then you can place the sodium into a calorimeter with a known mass of water and record the temperature change the water undergoes during the reaction. Then you can use the equation q(water)=m(water)c(water)ΔT to find the amount of heat absorbed by the water. since the amount of heat absorbed by the water is the amount of heat released from the sodium, q(sodium)=-q(water). Than you can use the equation q(sodium)=m(sodium)c(sodium)ΔT and solve for c(sodium)
I hope this helps and feel free to ask about anything that was unclear in the comments.
The concentration of the sulfuric acid : 0.499 M
The net ionic equation
2
OH
⁻(aq]+
2
H
⁺
(aq]
→
2
H
₂O
(l]
<h3>Further explanation</h3>
Given
42.68 ml of 0.43 M KOH
18.40 ml of H2SO4
Required
the concentration of the sulfuric acid
the net ionic equation
Solution
Acid-base titration formula
Ma. Va. na = Mb. Vb. nb
Ma, Mb = acid base concentration
Va, Vb = acid base volume
na, nb = acid base valence
Input the value :
a=KOH, b= H2SO4
0.43 x 42.68 x 1 = Mb x 18.40 x 2
Mb = 0.499 M
The net ionic equation
Reaction
2KOH + H2SO4 → K2SO4 + 2H2O
2
K
⁺
(aq]+
2
OH
⁻
(aq]
+
2
H
⁺
(aq]
+
SO
₄²⁻(aq]
→
2
K
⁺
(aq]
+
SO
₄²⁻(aq]
+
2
H
₂
O
(l]
canceled the spectator ions :
2
OH
⁻(aq]+
2
H
⁺
(aq]
→
2
H
₂O
(l]
The significant figures are always:
Different from zero except there are only zeros before the point.
You can round them to the previous significant.
In scientific notation, you have one figure point two more figures.
Examples:
You have 4.21
All different from zero and only two decimals.
Those are all significant figures.
if you have 000.231555
You will shorten this to two significant figures.
Before the point, you only have zeros, so you need to keep only one of them to say its less than one.
After the point, you have a lot of figures, but you need to round this to two.
Because you have a one before the three, you'll keep the three. If you have a five or bigger number, you round it.
In this case, you'll have 0.23 with two significant figures.
Answer:
0.5
Explanation:
1 mole of ammonium nitrate contains 2 moles of nirogen
1 mole of nitrogen converts to 0.5 moles of ammonium nitrate
the conversation factor is 0.5
The way an experiment is carried is out is determined by the purpose of that experiment.
