Answer:
<em>1. Genetic diversity</em> are the differences in DNA among individuals within a species or population while <em>ecosystem diversity</em> is the number or variety of ecosystems within a particular area.
2. <em>Genetic diversity
</em> is the genetic material of microorganisms, plants and animals contains information that determines the characteristics of all species and individuals that make up the diversity of the living world while the <em>ecosystem diversity</em> is the enormous range of terrestrial and aquatic environments on earth has been classified into a number of ecosystems.
Answer:
Electric field, E = 0.064 V/m
Explanation:
It is given that,
Resistivity of silver wire,
Current density of the wire,
We need to find the magnitude of the electric field inside the wire. The relationship between electric field and the current density is given by :
E = 0.0636 V/m
or
E = 0.064 V/m
So, the magnitude of electric field inside the wire is 0.064 V/m. Hence, this is the required solution.
Answer:
12000 N = 1223.66 kg
Explanation:
Because 1 newton is equal to 0.101971621 kilogram.
Answer:
<h2>
a) Q = 0.759µC</h2><h2>
b) E = 39.5µJ</h2>
Explanation:
a) The charge Q on the positive charge capacitor can be gotten using the formula Q = CV
C = capacitance of the capacitor (in Farads )
V = voltage (in volts) = 100V
C = ∈A/d
∈ = permittivity of free space = 8.85 × 10^-12 F/m
A = cross sectional area = 600 cm²
d= distance between the plates = 0.7cm
C = 8.85 × 10^-12 * 600/0.7
C = 7.59*10^-9Farads
Q = 7.59*10^-9 * 100
Q = 7.59*10^-7Coulombs
Q = 0.759*10^-6C
Q = 0.759µC
b) Energy stored in a capacitor is expressed as E = 1/2CV²
E = 1/2 * 7.59*10^-9 * 100²
E = 0.0000395Joules
E = 39.5*10^-6Joules
E = 39.5µJ