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aleksklad [387]

3 years ago

10

Dr. Evil stands on a 150 m high cliff and drops the kittens straight down. Fill out the following table that shows how the veloc

ity and acceleration of the kittens change with time during their fall.

1 answer:

riadik2000 [5.3K]3 years ago

3 0

I would say d if I remember right I think that’s what I put and got right sorry if it’s wrong

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What force works against friction? <br> Inertia<br> Potential <br> Kinetic

Oksanka [162]

Kinetic, as inertia means to remain unchanged.

6 0

4 years ago

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How big is the image produced by the periscope compared to the size of the object

ipn [44]

<span>As long as both mirrors are set at 45% and the same size then you see the same as is reflected in the upper mirror </span>

<span>Put a lens in the middle of the tube </span>

<span>? </span>

<span>We use mirrors when we drive cars ect </span>

<span>Normally they are set across from a concealed entrance or one that is hard to see both ways like the inside of a hairpin bend. Sometimes only to help in one direction. </span>

<span>Sonar which is sound waves that are sent out at a set rate then reflected by objects. The longer the gap between the two the further away it is, They still use periscopes to target boats though. </span>

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8 0

3 years ago

Energy that a microwave use to heat food?

yanalaym [24]

Electromagnetic energy

6 0

3 years ago

Can work be done on a system if there is no motion?

Minchanka [31]

Answer:

D) No, because of the way work is defined

Explanation:

The work done on an object is given by:

$W=Fd cos \theta$

where

F is the force applied on the object

d is the displacement of the object

$\theta$ is the angle between the direction of the force and the displacement

From the formula, we observe that if there is no motion involved, then the displacement of the object is zero:

d = 0

As a result, the product in the formula is also zero, therefore the work done will be zero as well.

5 0

3 years ago

The mean distance of an asteroid from the Sun is 2.98 times that of Earth from the Sun. From Kepler's law of periods, calculate

lutik1710 [3]

Answer:

The asteroid requires 5.14 years to make one revolution around the Sun.

Explanation:

Kepler's third law establishes that the square of the period of a planet will be proportional to the cube of the semi-major axis of its orbit:

$T^{2} = a^{3}$ (1)

Where T is the period of revolution and a is the semi-major axis.

In the other hand, the distance between the Earth and the Sun has a value of $1.50x10^{8} Km$ . That value can be known as well as an astronomical unit (1AU).

But 1 year is equivalent to 1 AU according with Kepler's third law, since 1 year is the orbital period of the Earth.

For the special case of the asteroid the distance will be:

$a = 2.98(1.50x10^{8}Km)$

$a = 4.47x10^{8}Km$

That distance will be expressed in terms of astronomical units:

$4.47x10^{8}Km.\frac{1AU}{1.50x10^{8}Km}$ ⇒ $2.98AU$

Finally, from equation 1 the period T can be isolated:

$T = \sqrt{a^{3}}$

$T = \sqrt{(2.98)^{3}}$

$T = \sqrt{26.463592}$

$T = 5.14AU$

Then, the period can be expressed in years:

$5.14AU.\frac{1yr}{1AU} ⇒ 5.14 yr$

$T = 5.14 yr$

Hence, the asteroid requires 5.14 years to make one revolution around the Sun.

8 0

3 years ago