From the stoichiometry of the balanced reaction equation, the correct statement are;
- For every 1 molecule of methane CH4 that reacts, 2 molecules of H2O are produced.
- For every 20 grams of methane (CH4) that reacts, 40 grams of H2O are produced.
- For every 200 moles of methane (CH4) that reacts, 400 moles of H2O are produced.
<h3>What is combustion?</h3>
The term combustion refers to the burning of fossil fuels for the purpose of energy production. The equation for reaction is CH4 + 2O2 ---> CO2 + 2H2O.
Using this equation as shown, the true statements are;
- For every 1 molecule of methane CH4 that reacts, 2 molecules of H2O are produced.
- For every 20 grams of methane (CH4) that reacts, 40 grams of H2O are produced.
- For every 200 moles of methane (CH4) that reacts, 400 moles of H2O are produced.
Learn more about combustion: brainly.com/question/15117038
1 property
2 procedure
Results
Answer:
0.55 mol Au₂S₃
Explanation:
Normally, we would need a balanced equation with masses, moles, and molar masses, but we can get by with a partial equation, if the S atoms are balanced.
1. Gather all the information in one place:
M_r: 34.08
Au₂S₃ + … ⟶ 3H₂S + …
m/g: 56
2. Calculate the moles of H₂S
Moles of H₂S = 56 g H₂S × (34.08 g H₂S/1 mol H₂S)
= 1.64 mol H₂S
3. Calculate the moles of Au₂S₃
The molar ratio is 1 mol Au₂S₃/3 mol H₂S.
Moles of Au₂S₃ = 1.64 mol H₂S × (1 mol Au₂S₃/3 mol H₂S)
= 0.55 mol Au₂S₃
