3 years ago

SCIENCE HELP MEEEE PLEASE

Physics

1 answer:

maks197457 [2]3 years ago

8 0

Answer:

lol no

Explanation:

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A toy car of mass 0.15kg accelerates from a speed of 10 cm/s to a speed of 15 cm/s. What is the impulse acting on the car?

OLga [1]

v=v2-v1=15-10=5 cm/s

p=mv=0.15•5=0.75 kg•cm/s

7 0

4 years ago

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Which statement about natural selection on early earth is correct?.

solong [7]

Answer:

wheres the statements

Explanation:

where its incomplete

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2 years ago

Alternating Current In Europe, the voltage of the alternating current coming through an electrical outlet can be modeled by the

stealth61 [152]

Answer:

$\frac{50}{\pi }$ Hz

Explanation:

In alternating current (AC) circuits, voltage (V) oscillates in a sine wave pattern and has a general equation as a function of time (t) as follows;

V(t) = V sin (ωt + Ф) -----------------(i)

Where;

V = amplitude value of the voltage

ω = angular frequency = 2 π f [f = cyclic frequency or simply, frequency]

Ф = phase difference between voltage and current.

Now,

From the question,

V(t) = 230 sin (100t) ---------------(ii)

By comparing equations (i) and (ii) the following holds;

V = 230

ω = 100

Ф = 0

But;

ω = 2 π f = 100

2 π f = 100 [divide both sides by 2]

π f = 50

f = $\frac{50}{\pi }$ Hz

Therefore, the frequency of the voltage is $\frac{50}{\pi }$ Hz

7 0

3 years ago

What speed would a fly with a mass of 0.72 g need in order to have the same kinetic energy as a 1250 kg automobile traveling at

Elena L [17]

Kinetic of automobile

Mass m = 1,250 Kg; V = 11 m/s

Formula: K.E = 1/2 mV²

K.E = 1/2(1,250 Kg)(11 m/s)²

K.E = 75,625 J

Speed required for insect to have the same kinetic energy as automobile

Mass of insect = 0.72 g convert to Kg m = 7.2 x 10⁻⁴ Kg

K.E = 1/2 mV² Derive V =?

V = 2 K.E/m

V = √2(75,625 J)/7.2 x 10⁻4 Kg

V = √2.1 x 10⁸ m²/s²

V = 14,491.34 m/s (velocity of insect)

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3 years ago

A diver is on a board 3.00 m above the water . She jumps straight up at 3.25 m/s. . How many seconds later does she hit the wate

zzz [600]

Answer:

1.18 sec

Explanation:

v = 0

u = 3.25m/s

v = u - gt

t1 = u/g = 3.25/9.8 = 0.332 s

height above board = v²/2g =

3.25²/(2×9.8) = 0.54 m

time to fall from there to water

t2 = √(2h/g) = √(2(3+ 0.54)/9.8) = 0.85 s

total time = t1 + t2

total time = 0.85 + 0.332 = 1.182 s

6 0

3 years ago