Answer: Concentration of 
in the equilibrium mixture is 0.31 M
Explanation:
Equilibrium concentration of 
= 0.729 M
The given balanced equilibrium reaction is,
Initial conc. x 0 0
At eqm. conc. (x-2y) M (y) M (3y) M
The expression for equilibrium constant for this reaction will be:
3y = 0.729 M
y = 0.243 M
![K_c=\frac{[y]\times [3y]^3}{[x-2y]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5By%5D%5Ctimes%20%5B3y%5D%5E3%7D%7B%5Bx-2y%5D%5E2%7D)
Now put all the given values in this expression, we get :
concentration of in the equilibrium mixture = 
Thus concentration of in the equilibrium mixture is 0.31 M
Answer:
Only the H is unbalanced.
Explanation:
There are 4 H's and 2 of everything else
A metal that would be magnetic is nickel
14 neutrons... hope it is correct!!!!!!!!
From the reaction: <span>caco3(s) → cao(s) + co2(g) it can be seen that,
1 mol (i.e. 100 g) of CaCO3 gives 1 mol (i.e. 44 g) of CO2
Now, number of moles of CaCO3 present in reaction system,
</span>=
=
= 0.45 mol
So, 0.45 mol of CaCO3 will give 0.45 mol of CO2.
From ideal gas equation, we know that PV = nRT
V =
.
Given that, P = 645 torr = 0.8487 atm (Since, 1 atm = 760 torr)
Therefore, V =
= 34.8 l
