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bazaltina [42]
2 years ago
14

NEED HELP!! What types of waves are transmitted from the H-E-L-P device ?

Chemistry
1 answer:
IrinaVladis [17]2 years ago
5 0

Answer:

What do you mean need more details

Explanation:

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The equilibrium constant, Kc, for the following reaction is 0.967 at 650 K. 2NH3(g) N2(g) 3H2(g) When a sufficiently large sampl
AlekseyPX

Answer: Concentration of NH_3 in the equilibrium mixture is 0.31 M

Explanation:

Equilibrium concentration of H_2 = 0.729 M

The given balanced equilibrium reaction is,

                 2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g)

Initial conc.            x                0           0

At eqm. conc.     (x-2y) M     (y) M   (3y) M

The expression for equilibrium constant for this reaction will be:

3y = 0.729 M

y = 0.243 M

K_c=\frac{[y]\times [3y]^3}{[x-2y]^2}

Now put all the given values in this expression, we get :

K_c=\frac{0.243\times (0.729)^3}{(x-2\times 0.243)^2}

0.967=\frac{0.243\times (0.729)^3}{(x-2\times 0.243)^2}

x=0.80

concentration of NH_3 in the equilibrium mixture = 0.80-2\times 0.243=0.31

Thus concentration of NH_3 in the equilibrium mixture is 0.31 M

3 0
3 years ago
Which element or elements are unbalanced in this equation?
Stells [14]

Answer:

Only the H is unbalanced.

Explanation:

There are 4 H's and 2 of everything else

7 0
3 years ago
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Name a metal that would be magnetic
eimsori [14]
A metal that would be magnetic is nickel
7 0
3 years ago
For Al, its atomic number is 13 and its mass number is 27. How many neutrons does it have?
poizon [28]
14 neutrons... hope it is correct!!!!!!!!
3 0
3 years ago
Read 2 more answers
What volume of co2 gas at 645 torr and 800. k could be produced by the decomposition of 45.0 g of caco3? caco3(s) → cao(s) + co2
AysviL [449]
From the reaction: <span>caco3(s) → cao(s) + co2(g) it can be seen that,
1 mol (i.e. 100 g) of CaCO3 gives 1 mol (i.e. 44 g) of CO2
Now, number of moles of CaCO3 present in reaction system,
</span>= \frac{weight of CaCO3 (g)}{gram molecular weight}
= \frac{45}{100} = 0.45 mol

So, 0.45 mol of CaCO3 will give 0.45 mol of CO2.

From ideal gas equation, we know that PV = nRT
V = \frac{nRT}{P}.
Given that, P = 645 torr = 0.8487 atm (Since, 1 atm = 760 torr)
Therefore, V = \frac{0.45 X 0.08206 X 800}{0.8487}

= 34.8 l
5 0
3 years ago
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