Answer:
9.1 KJ
Explanation:
First we must find the number of moles of HBr involved;
number of moles of HBr= mass of HBr/ molar mass of HBr
But molar mass of HBr= 80.91 g/mol
Given mass of HBr from the question= 20.1g
Hence;
Number of moles of HBr= 20.1 g/80.91g
Number of moles of HBr= 0.25 moles of HBr
If 2 moles of HBr has a heat of formation of 72.80KJ
Then 0.25 moles of HBr will have a heat of formation of 0.25× 72.80/2= 9.1 KJ
Therefore; 20.1 g of HBr will have a heat of formation of 9.1 KJ
Carbon Dioxide with water and sunlight produce glucose and oxygen
2NOCl ⇄ 2NO + Cl₂
K = [NO]²[Cl₂]/[NOCl]
K = [0,0012]²[0,0022]/[0,014]²
K = 0,000000003/0,000196
K = 0,000016163
