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Lady bird [3.3K]
3 years ago
13

Help me with these please

Chemistry
1 answer:
olga55 [171]3 years ago
4 0

Answer:

Help you with what hmm I do not know what you are talking about

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Covalent bonds form between hydrogen and oxygen atoms in a water molecule as a result of:
puteri [66]
Covalent bonds form between hydrogen and oxygen atoms in a water molecule as a result of - Sharing of electrons between atoms.
5 0
4 years ago
8. What is the mass of 4.50 x 1022 Cu atoms?​
vladimir2022 [97]

Answer:

4.7485 g

Explanation:

4.50 x 10^22 Cu atoms * (1 mol Cu / 6.022 x 10^23 Cu atoms) * 63.546 g Cu/(mol Cu) = 4.7485 g

In every mole of Cu, there are 6.022 x 10^23 atoms (Avogadro's number). The molecular weight of copper is 63.546 g/mol.

5 0
3 years ago
How many molecules of water can be produced from 46.72 liters of C8H18? 2\:C_8H_{18}\:+\:25\:O_2\:\:\Longrightarrow\:\:16\:CO_2\
Dmitry [639]

Answer:

1.13×10^25 molecules of water.

Explanation:

Equation of the reaction;

C8H18(g) + 25/2 O2 (g) -------> 8CO2(g) + 9H2O(l)

It is important to first put down the balanced reaction equation. It is not possible to solve any problem on stoichiometric relationship without a balanced reaction equation. Once the equation is obtained, we can now proceed with other steps in the solution of the problem.

From the reaction equation, 1 mole of C8H18 produces 9 moles of water

1 mole of C8H18 occupies 22.4L volume while 1 mole of water contains 6.02×10^23 molecules of water

Hence

22.4 L of C8H18 produces 9(6.02×10^23) molecules of water

46.72 L of C8H18 will produce 46.72 L × 9(6.02×10^23) molecules of water/22.4 L

= 113×10^23 or 1.13×10^25 molecules of water.

5 0
3 years ago
A blood sample with a known glucose concentration of 102.0 mg/dL is used to test a new at home glucose monitor. The device is us
Zinaida [17]

Answer:

A. 96.3 mg/dL

Absolute error: 5.7 mg/dL

Relative error: 5.6%

B. 97.2 mg/dL

Absolute error: 4.8 mg/dL

Relative error: 4.7%

C. 104.8 mg/dL

Absolute error: 2.8 mg/dL

Relative error: 2.7%

D. 111.5 mg/dL

Absolute error: 9.5 mg/dL

Relative error: 9.3%

E. 110.5 mg/dL

Absolute error: 8.5 mg/dL

Relative error: 8.3%

Explanation:

The formula for the absolute error is:

Absolute error = |Actual Value - Measured Value|

The formula for the relative error is:

Relative error = |Absolute error/Actual value|

In your exercise, we have that

Actual Value = 102.0 mg/dL

A. 96.3 mg/dL:

E_{ABS} = |102.0 - 96.3| = 5.7mg/dL

E_{R} = \frac{5.7}{102} = 0.056 = 5.6%

B. 97.2 mg/dL

E_{ABS} = |102.0 - 97.2| = 4.8mg/dL

E_{R} = \frac{4.8}{102} = 0.047 = 4.7%

C. 104.8 mg/dL

E_{ABS} = |102.0 - 104.8| = 2.8mg/dL

E_{R} = \frac{2.8}{102} = 0.027 = 2.7%

D. 111.5 mg/dL

E_{ABS} = |102.0 - 111.5| = 9.5mg/dL

E_{R} = \frac{9.5}{102} = 0.093 = 9.3%

E. 110.5 mg/dL

E_{ABS} = |102.0 - 111.5| = 8.5mg/dL

E_{R} = \frac{8.5}{102} = 0.083 = 8.3%

4 0
4 years ago
If water with a mass of 25.0 grams freezes in a closed system such as a closed glass jar, what is the mass of the formed ice aft
uranmaximum [27]
The mass would still be the same 25.0 g but the volume would be bigger
3 0
3 years ago
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