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Stels [109]
3 years ago
11

If a seed grows well in a very salty environment then that seed has a high salt tolerance.

Chemistry
2 answers:
garik1379 [7]3 years ago
6 0
That answer is true
erica [24]3 years ago
3 0
The answer is True!!
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How did the masses of objects affect the strength of gravity
omeli [17]

Answer:

the strength of gravitational force between two objects depends on two factors,mass and distance. the force of gravity the masses exert on each other. if one of the masses is doubled, the Force of gravity between the object is doubled. increases the force of gravity decreases.

5 0
3 years ago
What are
Vesna [10]

Answer:

carbohydrates

Explanation:

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7 0
3 years ago
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The density of octane is 0.700 g/cm3.  What is the mass of one liter of octane?
Gelneren [198K]

Answer:

m = 700 g

Explanation:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Symbol:

The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.

Given data:

Density of octane = 0.700 g/cm³

Volume = 1 L

Mass = ?

Formula:

D=m/v

D= density

m=mass

V=volume

First of all we will convert the volume in cm³ because density is given in g/cm³ unit.

1 L = 1000 cm³

Now we will put the values in formula:

d= m/v

m = v × d

m = 1000 cm³ × 0.700 g/cm³

m = 700 g

5 0
3 years ago
State two applications of simple distillation of separating mixture​
Salsk061 [2.6K]

Answer:

Purify drinking water of unwanted

  • chemicals and
  • minerals such as salt.

<em>Hope this helps! :D</em>

3 0
3 years ago
If a gas is moved from a large container to a small container but its temperature and number of moles remain the same, what woul
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To solve this we assume that the gas is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant temperature and number of moles of the gas the product of PV is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

 

P1V1 =P2V2

<span>P2 = P1V1/V2</span>

<span>
</span>

<span>The correct answer is the first option. Pressure would increase. This can be seen from the equation above where V2 is indirectly proportional to P2.</span>

8 0
3 years ago
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