Explanation :
(a) 
This reaction is combustion reaction in which an oxygen react with a molecule to give its corresponding oxides ans water molecule.
(b) 
This reaction is a redox reaction or oxidation-reduction reaction in which sulfur get oxidized and oxygen get reduced.
(c) 
This reaction is a combination reaction in which the two reactants molecule combine to form a large molecule or product.
(d) 
This reaction is a decomposition reaction in which a large molecule or reactant decomposes to give two or more molecule or products.
(e) 
This reaction is a double displacement reaction in which the cation of two reactants molecule exchange their places to give two different products.
(f) 
This reaction is a combination reaction in which the two reactants combine to form a large molecule or product.
(g) 
This reaction is a double displacement reaction in which the cation of two reactants molecule exchange their places to give two different products.
(h) 
This reaction is combustion reaction in which a hydrocarbon react with an oxygen to give carbon dioxide and water as a products.
Chemical formula of the glucose: C₆H₁₂O₆
We calculate the molar mass:
atomic mass (C)=12 u
atomic mass (H)=1 u
atomic mass (O)=16 u
atomic weight (C₆H₁₂O₆)=6(12 u)+12(1u)+6(16 u)=72 u+12u+96 u=180 u.
Therefore : 1 mol of glucose will be 180 g
The molar mass would be: 180 g/ mol
2) we calculate the number of moles of 1.5 g.
180 g---------------------1 mol
1.5 g---------------------- x
x=(1.5 g * 1 mol) / 180 g≈8.33*10⁻³ moles
we knows that:
1 mol = 6.022 * 10²³ particles (atoms or molecules)
3)We calculate the number of molecules:
Therefore:
1 mol-----------------------6.022*10²³ molecules of glucose
8.33*10⁻³ moles-------- x
x=(8.33*10⁻³ moles * 6.022*10²³ molecules)/1 mol≈5.0183*10²¹ molecules.
4)We calculate the number of C, H and O atoms:
A molecule of glucose have 6 atoms of C, 12 atoms of H, and 6 atoms of O,
number of atoms of C=(6 atoms/1 molecule)(5.0183*10²¹molecules)≈
3.011*10²²
number of atoms of H=(12 atoms/1 molecule)(5.0183*10²¹ molecules)≈
6.022*10²² .
number of atoms of O=(6 atoms/1 molecule)(5.0183*10²¹ molecules)≈
3.011*10²²
Answer: we have 3.011*10²² atoms of C, 6.022*10²² atoms of H, and 3.011*10²² atoms of O.
Answer:
from the ideal gas law, P2 /P1 = T2 /T1 for the same volume and quantity of gas. P2 = (758 mmHg) (45 +273 K) / (15 +273K) = 837 mmHg.
Explanation:
Answer :
(a) 0.0152
(b) 0.0000000778
(c) 0.000001
(d) 1600.1
Explanation :
Scientific notation : It is the representation of expressing the numbers that are too big or too small and are represented in the decimal form with one digit before the decimal point times 10 raise to the power.
For example :
5000 is written as 
889.9 is written as 
In this examples, 5000 and 889.9 are written in the standard notation and and are written in the scientific notation.
(a) 
The standard notation is, 0.0152
(b) 
The standard notation is, 0.0000000778
(c) 
The standard notation is, 0.000001
(d) 
The standard notation is, 1600.1
Answer:
the answer should 126 859.2 m2
