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Kipish [7]
3 years ago
15

Dos moléculas de Clorato de Potasio en estado sólido, al aplicarle calor se descompone en dos moléculas de Cloruro de Potasio en

estado sólido y tres moléculas diatómicas de Oxígeno en estado gaseoso ¿como se representan?
Chemistry
1 answer:
DedPeter [7]3 years ago
7 0

Answer:

2KClO3 (s) -------> 2KCl (s) + 3O2 (g)

Explanation:

Una ecuación de reacción química es una representación simbólica de lo que sucede en un recipiente de reacción.

Al escribir la ecuación de reacción química para una reacción particular, se utilizan los símbolos químicos de todas las especies involucradas.

Por la reacción. en el cual dos moléculas de Clorato de Potasio en estado sólido, al aplicar calor se descompone en dos moléculas de Cloruro de Potasio en estado sólido y tres moléculas diatómicas de Oxígeno en estado gaseoso, la ecuación de reacción se escribe así;

2KClO3 (s) -------> 2KCl (s) + 3O2 (g)

La regla para escribir ecuaciones de reacción química balanceada es que el número de átomos de cada elemento en el lado derecho de la ecuación de reacción debe ser el mismo que el número b de átomos del mismo elemento en el lado izquierdo de la ecuación de reacción.

Si realizamos un conteo de átomos simple en ambos lados de la ecuación de reacción, la regla se cumple

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Calculate the standard potential for the following galvanic cell: Fe(s) | Fe2+(aq) || Ag+(aq) | Ag(s) which has the overall bala
Nataly [62]

Answer:

E° = 1.24 V

Explanation:

Let's consider the following galvanic cell: Fe(s) | Fe²⁺(aq) || Ag⁺(aq) | Ag(s)

According to this notation, Fe is in the anode (where oxidation occurs) and Ag is in the cathode (where reduction occurs). The corresponding half-reactions are:

Anode: Fe(s) ⇒ Fe²⁺(aq) + 2 e⁻

Cathode: Ag⁺(aq) + 1 e⁻ ⇒ Ag(s)

The standard cell potential (E°) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.

E° = E°red, cat - E°red, an

E° = 0.80 V - (-0.44 V) = 1.24 V

6 0
3 years ago
If 120 g of potassium chloride are mixed with 100 g of water at 80°C, how much will not dissolve?
djverab [1.8K]

Answer:

yes

Explanation:

How many grams of KCl will dissolve in 1 liter of H2O at 50 °C? 5. 58.0 g of K2Cr2O7 is added to 100 g H2O at. 0 °C. With constant stirring, to what temp-.

4 0
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How does the total volume of gas particles compare to the volume of the space between gas particles?
saw5 [17]
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             There is more space between gas particles than the size of the particles.

Explanation:
                   This scenario can be understand by taking a very simple example. As we know that 1 mole of any gas at standard temperature and pressure occupy 22.4 liters of volume. Lets take Hydrogen gas and Oxygen gas, 1 mole of each gas will occupy same volume. Why it is so? Why same volume although Oxygen is 16 times more heavier? This is because the space between gas molecules is very large. Approximately the distance between gas molecules is 300 times greater than their own diameter from its neighbor molecules. 
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4.2g of sodium bicarbonate is equivalent to how many moles of sodium bicarbonate
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<span>The mass of one mole of sodium bicarbonate (aka NaHCO3) is equal to 1 * 22.99g/mol + 1 * 1.00g/mol + 1 * 12.01g/mol + 3 * 16.00g/mol = 83.91g/mol. From this, we can convert 4.2g of NaHCO3 to moles by dividing by 83.91g/mol, to get 0.050 moles of sodium bicarbonate.</span>
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3 years ago
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Neko [114]
In descending order from top:

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