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Kipish [7]
3 years ago
15

Dos moléculas de Clorato de Potasio en estado sólido, al aplicarle calor se descompone en dos moléculas de Cloruro de Potasio en

estado sólido y tres moléculas diatómicas de Oxígeno en estado gaseoso ¿como se representan?
Chemistry
1 answer:
DedPeter [7]3 years ago
7 0

Answer:

2KClO3 (s) -------> 2KCl (s) + 3O2 (g)

Explanation:

Una ecuación de reacción química es una representación simbólica de lo que sucede en un recipiente de reacción.

Al escribir la ecuación de reacción química para una reacción particular, se utilizan los símbolos químicos de todas las especies involucradas.

Por la reacción. en el cual dos moléculas de Clorato de Potasio en estado sólido, al aplicar calor se descompone en dos moléculas de Cloruro de Potasio en estado sólido y tres moléculas diatómicas de Oxígeno en estado gaseoso, la ecuación de reacción se escribe así;

2KClO3 (s) -------> 2KCl (s) + 3O2 (g)

La regla para escribir ecuaciones de reacción química balanceada es que el número de átomos de cada elemento en el lado derecho de la ecuación de reacción debe ser el mismo que el número b de átomos del mismo elemento en el lado izquierdo de la ecuación de reacción.

Si realizamos un conteo de átomos simple en ambos lados de la ecuación de reacción, la regla se cumple

You might be interested in
Molecule of dissimilar elements with a net charge remaining is called
MariettaO [177]
It is called a polyatomic ion. 

 Hope this helps!!!
3 0
3 years ago
Which is a nonmetal that becomes isoelectronic with argon<br> when it forms its most common ion?
mrs_skeptik [129]

Answer:sulfur

Explanation:

6 0
3 years ago
How much water, in grams, can be made from 1.03 x <img src="https://tex.z-dn.net/?f=10%5E%7B24%7D" id="TexFormula1" title="10^{2
krok68 [10]

Answer:

30.8 g of water are produced

Explanation:

First of all we need the equation for the production of water:

2H₂ + O₂ → 2H₂O

2 moles of hydrogen react with 1 mol of oxygen in order to produce 2 moles of water.

As we assume, the oxygen in excess, we determine the moles of H₂.

1.03ₓ10²⁴ molecules . 1 mol/ 6.02ₓ10²³ molecules = 1.71 moles

Ratio is 2:2, so 1.71 moles will produce 1.71 moles of water

Let's convert the moles to mass: 1.71 mol . 18g / 1mol = 30.8 g of water are produced

5 0
4 years ago
A sample of nitrogen occupies 10.0 liters at 25°C and 98.7 kPa. What would be the volume at 20°C and 102.7 kPa?
krek1111 [17]
To solve the problem, we assume the sample to be ideal. Then, we use the ideal gas equation which is expressed as PV = nRT. From the first condition of the nitrogen gas sample, we calculate the number of moles.

n = PV / RT
n = (98.7x 10^3 Pa x 0.01 m^3) / (8.314 Pa m^3/ mol K) x 298.15 K
n = 0.40 mol N2

At the second condition, the number of moles stays the same however pressure and temperature was changed. So, the new volume is calculated as follows:

V = nRT / P
V = 0.40 x 8.314 x 293.15 / 102.7 x 10^3
V = 9.49 x 10^-3 m^3 or 9.49 L
7 0
3 years ago
If the atmospheric pressure is 0.975 atm what is the pressure of the enclosed gas
Nuetrik [128]
Missing in your question:
Picture (1)
when its an open- tube manometer and the h = 52 cm. 
when the pressure of the atmosphere is equal the pressure of the gas plus the pressure from the mercury column 52 Cm so, we can get the pressure of the gas from this formula:
P(atm) = P(gas) + height (Hg)
∴P(gas) = P(atm) - height (Hg)
              = 0.975 - (520/760) 
              = 0.29 atm
Note: I have divided 520 mm Hg by 760 to convert it to atm
Picture (2)
The pressure of the gas is the pressure experts by the column of mercury and when we have the Height (Hg)= 67mm 
So the pressure of the gas =P(atm) + Height (Hg)
                                             =  0.975 + (67/ 760) = 1.06 atm
Picture (3) 
As the tube is closed SO here the pressure of the gas is equal the height of the mercury column, and when we have the height (Hg) = 103 mm. so, we can get the P(gas) from this formula:
P(gas) = Height(Hg)
           = (103/760) = 0.136 atm

6 0
3 years ago
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