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jekas [21]
3 years ago
7

A container holds 100.0 mL of nitrogen at 21° C and a pressure of 736 mm Hg. What will be its volume if the temperature increase

s by 35° C?
Chemistry
1 answer:
devlian [24]3 years ago
5 0

Answer:

V₂ = 104.76 mL

Explanation:

Given data:

Initial volume = 100.0 mL

Initial temperature = 21°C (21 + 273.15 K = 294.15 K)

Final temperature = 35°C (35 + 273.15 K = 308.15 k)

Final volume = ?

Solution:

Charles Law:

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ =100.0 mL × 308.15 K / 294.15 K

V₂ = 30815 mL.K /294.15 K

V₂ = 104.76 mL

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Answer:

To determine whether a given single replacement will occur, you must use an “Activity Series” table. If the metal or the halogen is above the element it will replace based on the activity series, a single displacement reaction will occur. The video below summarizes an experiment conducted to compare the activities of three metals ( Mg, Cu and Zn ).

Explanation:

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2 years ago
Consider the following reaction: 2 NO(g) + 5 H2(g) → 2 NH3(g) + 2 H2O(g) Which set of solution maps would be needed to calculate
Leto [7]

Answer : The correct option is, (I) gNO\rightarrow molNO\rightarrow molNH_3\rightarrow gNH_3

Solution : Given,

Mass of NO = 45.8 g

Mass of H_2 = 12.4 g

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Molar mass of H_2 = 2 g/mole

Molar mass of NH_3 = 17 g/mole

First we have to calculate the moles of NO and O_2.

\text{ Moles of }NO=\frac{\text{ Mass of }NO}{\text{ Molar mass of }NO}=\frac{45.8g}{30g/mole}=1.53moles

\text{ Moles of }H_2=\frac{\text{ Mass of }H_2}{\text{ Molar mass of }H_2}=\frac{12.4g}{2g/mole}=6.20moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

2NO(g)+5H_2(g)\rightarrow 2NH_3(g)+2H_2O(g)

From the balanced reaction we conclude that

As, 2 mole of NO react with 5 mole of H_2

So, 1.53 moles of NO react with \frac{1.53}{2}\times 5=3.82 moles of H_2

From this we conclude that, H_2 is an excess reagent because the given moles are greater than the required moles and NO is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of NH_3

From the reaction, we conclude that

As, 2 mole of NO react to give 2 mole of NH_3

So, 1.53 mole of NO react to give 1.53 mole of NH_3

Now we have to calculate the mass of NH_3

\text{ Mass of }NH_3=\text{ Moles of }NH_3\times \text{ Molar mass of }NH_3

\text{ Mass of }NH_3=(1.53moles)\times (17g/mole)=26.0g

Therefore, the maximum mass of NH_3 produced 26.0 grams.

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What functional feature(s) does the phosphate group contribute to the structure of a phospholipid? select all that apply. select
bezimeni [28]
A phospholipid structure is shown in the picture attached. It has three parts: the hydrophobic tail, the hydrophilic head and the phosphate group in the center. Thus, the function of the phosphate group is to link the hydrophobic and hydrophilic parts of a phospholipid. Specifically, the phosphate group is part of the hydrophilic head. So, it is used to connect the phospholipids to polar compounds.

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3 years ago
How do we find the number of electrons in an atom?
Anon25 [30]

I Believe this is the right answer:

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