Answer:
![\dot W_{out} = 3863.98\,kW](https://tex.z-dn.net/?f=%5Cdot%20W_%7Bout%7D%20%3D%203863.98%5C%2CkW)
Explanation:
The turbine at steady-state is modelled after the First Law of Thermodynamics:
![-\dot Q_{out} -\dot W_{out} + \dot m \cdot (h_{in}-h_{out}) = 0](https://tex.z-dn.net/?f=-%5Cdot%20Q_%7Bout%7D%20-%5Cdot%20W_%7Bout%7D%20%2B%20%5Cdot%20m%20%5Ccdot%20%28h_%7Bin%7D-h_%7Bout%7D%29%20%3D%200)
The specific enthalpies at inlet and outlet are, respectively:
Inlet (Superheated Steam)
![h_{in} = 3353.1\,\frac{kJ}{kg}](https://tex.z-dn.net/?f=h_%7Bin%7D%20%3D%203353.1%5C%2C%5Cfrac%7BkJ%7D%7Bkg%7D)
Outlet (Liquid-Vapor Mixture)
![h_{out} = 890.1\,\frac{kJ}{kg}](https://tex.z-dn.net/?f=h_%7Bout%7D%20%3D%20890.1%5C%2C%5Cfrac%7BkJ%7D%7Bkg%7D)
The power produced by the turbine is:
![\dot W_{out}=-\dot Q_{out} + \dot m \cdot (h_{in}-h_{out})](https://tex.z-dn.net/?f=%5Cdot%20W_%7Bout%7D%3D-%5Cdot%20Q_%7Bout%7D%20%2B%20%5Cdot%20m%20%5Ccdot%20%28h_%7Bin%7D-h_%7Bout%7D%29)
![\dot W_{out} = -2.93\,kW + (1.57\,\frac{kg}{s} )\cdot (3353.1\,\frac{kJ}{kg} - 890.1\,\frac{kJ}{kg} )](https://tex.z-dn.net/?f=%5Cdot%20W_%7Bout%7D%20%3D%20-2.93%5C%2CkW%20%2B%20%281.57%5C%2C%5Cfrac%7Bkg%7D%7Bs%7D%20%29%5Ccdot%20%283353.1%5C%2C%5Cfrac%7BkJ%7D%7Bkg%7D%20-%20890.1%5C%2C%5Cfrac%7BkJ%7D%7Bkg%7D%20%29)
![\dot W_{out} = 3863.98\,kW](https://tex.z-dn.net/?f=%5Cdot%20W_%7Bout%7D%20%3D%203863.98%5C%2CkW)
Answer:
//The program prompts user to input three integers and it displays them, adds and gets their average
//begin
public class Test
{
public static void Main()
{
//input intergers
int[] score = new int[3];
int avg,rem,sum = 0;
for(int i=0;i<3;i++)
{
Console.WriteLine("Enter an integer score ");
score[i] = Convert.ToInt32(Console.ReadLine());
sum = sum + score[i];
}
avg = sum/3;
rem = sum%3;
Console.WriteLine("The average of "+score[0]+","+score[1]+","+score[2]+" is "+avg +" with a remainder of "+rem);
}
}