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Nadya [2.5K]
3 years ago
8

What did the gold foil experiment indicate about the atom

Chemistry
1 answer:
Delicious77 [7]3 years ago
7 0
It’s the joe connected with mama
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Describe how the properties of elements in the same group differ to the properties of elements in the same period
Fofino [41]

Answer:

(a) (i) All the elements of a group have similar chemical properties because they have same no. of valence electrons in their outermost shell. (ii) All the elements of a period have different chemical properties because they have different no. of valence electrons in their atoms.

5 0
3 years ago
Determine the number of atoms of O in 92.3 moles of Cr3(PO4)2
Irina18 [472]

739 is the number of atoms of O in 92.3 moles of Cr3(PO4)2.

Explanation:

Molecular formula given is  = Cr3(PO4)2

number of moles of the compound is 92.3 moles

number of 0 atoms in 92.3 moles =?

From the chemical formula 1 mole of the compound has 8 atoms of oxygen

So, it can be written as

1 mole Cr3(PO4)2 has 8 atoms of oxygen

92.3 moles of Cr3(PO4)2 has x atoms of oxygen

\frac{8}{1} = \frac{x}{92.3}

x = 8 x 92.3

x = 738.4 atoms

There will be 739 oxygen atoms in the 92.3 moles of Cr3(PO4)2.

4 0
3 years ago
What is the concentration of the unknown h3po4 solution? the neutralization reaction ish3po4(aq)+3naoh(aq)→3h2o(l)+na3po4(aq) -g
hjlf
First, we need to get moles of NaOH:

when moles NaOH = volume * molarity 

                                  = 0.02573L * 0.11 M

                                 = 0.0028 moles 

from the reaction equation:

H3PO4(aq) + 3NaOH → 3 H2O(l) + Na3PO4(aq)

we can see that when 1 mol H3PO4 reacts with→ 3 mol NaOH

 ∴ X mol H3PO4 reacts with → 0.0028 moles NaOH

∴ moles H3PO4 = 0.0028 mol / 3 = 9.4 x 10^-4 mol

now we can get the concentration of H3PO4:

∴[H3PO4] = moles H2PO4 / volume

               = 9.4 x 10^-4 / 0.034 L

               = 0.028 M
6 0
3 years ago
Read 2 more answers
A chemist prepares a solution of copper(II) sulfate CuSO4 by measuring out 31.μmol of copper(II) sulfate into a 150.mL volumetri
baherus [9]

Answer:

The concentration of the copper (II) sulfate solution is 2.06 * 10^2 μmol/L or 2.06 * 10^2 μM

Explanation:

The concentration of a solution is the amount of solute dissolved in a given volume of solution. In this case, the concentration of the copper(II) sulfate solution in micromoles per liter (symbol ) is the number of micromoles of copper(II) sulfate dissolved in each liter of solution. To calculate the micromoles of copper(II) sulfate dissolved in each liter of solution you must divide the total micromoles of solute by the number of liters of solution.

Here's that idea written as a formula: c= n/V

where c stands for concentration, n stands for the total micromoles of copper (II) sulfate and V stands for the total volume of the solution.

You're not given the volume of the solution in liters, but rather in milliliters. You can convert milliliters to liters with a unit ratio: V= 150. mL * 10^-3 L/ 1 mL = 0.150 L

Next, plug in μmol and liters into the formula to divide the total micromoles of solute by the number of liters of solution: c= 31 μmol/0.150 L = 206.66 μmol/L

Convert this number into scientific notation: 2.06 * 10^2 μmol/L or 2.06 * 10^2 μM

3 0
2 years ago
Which factor has the least effect on the rate of solution of a solid in a liquid?
vitfil [10]
The pressure will not affect the rate of solution.
4 0
3 years ago
Read 2 more answers
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