Answer:
The amount of NaOH required to prepare a solution of 2.5N NaOH.
The molecular mass of NaOH is 40.0g/mol.
Explanation:
Since,
NaOH has only one replaceable -OH group.
So, its acidity is one.
Hence,
The molecular mass of NaOH =its equivalent mass
Normality formula can be written as:
Substitute the given values in this formula to get the mass of NaOH required.

Hence, the mass of NaOH required to prepare 2.5N and 1L. solution is 100g
Shielding effect being attendency of the inner electrons to repel the outermost electrons, an increase in shielding effect increases atomic radius and decrease reduces the atomic radius
Answer:
There are 0.0186 moles of formula units in 6.35 grams of aluminum sulfate
.
Explanation:
What's the empirical formula of aluminum sulfate?
Sulfate is an anion with a charge of -2 per ion. When sulfate ions are bonded to metals, the compound is likely ionic.
Aluminum is a group III metal. Its ions tend to carry a charge of +3 per ion.
The empirical formula of an ionic compound shall balance the charge on ions with as few ions as possible.
The least common multiple of 2 and 3 is 6. That is:
- Three sulfate ions
will give a charge of -6. - Two aluminum ions
will give a charge of +6.
Pairing three
ions with two
will balance the charge. Hence the empirical formula:
.
What's the mass of one mole of aluminum sulfate? In other words, what's the formula mass of
?
Refer to a modern periodic table for relative atomic mass data:
- Al: 26.982;
- S: 32.06;
- O: 15.999.
There are
- two Al,
- three S, and
- twelve O
in one formula unit of
.
Hence the formula mass of
:
.
How many moles of formula units in 6.35 grams of
?
.
The answer would be B) Dunes. I hope you have a wonderful day :)
The real thing is reaallly tiny, you won't be able to view it with a microscope. that's why models are used to study atoms.