Atomic mass Ca = 40.078 a.m.u
40.078 g -------------------- 6.02x10²³ atoms
72.8 g ---------------------- ??
72.8 x ( 6.02x10²³) / 40.078 =
4.38x10²⁵ / 40.078 = 1.093x10²⁴ atoms
hope this helps!
• Take a look at the steps below to see how to balance this equation. Let's start by writing the unbalanced equation given the information.
Unbalanced Equation : C₃H₈ (g) + O₂ (g) → CO₂ (g) + H₂O (g)
,
Start by Balancing the Carbons : C₃H₈ (g) + O₂ (g) → 3CO₂ (g) + H₂O (g)
Now let's balance the Hydrogen : C₃H₈ (g) + O₂ (g) → 3CO₂ (g) + 4H₂O (g)
Balancing the Oxygen : C₃H₈ (g) + 5O₂ (g) → 3CO₂ (g) + 4H₂O (g)
Balanced Equation : C₃H₈ (g) + 5O₂ (g) → 3CO₂ (g) + 4H₂O (g)
• Let's apply dimensional analysis here,
0.7 L propane × (5 liters Oxygen / 1 liter Propane) = 3.5 Liters of Oxygen
• Similarly we can identify the liters of carbon dioxide produced in the reaction,
0.7 L propane × (3 liters Carbon Dioxide / 1 liter Propane) = 2.1 Liters of Carbon Dioxide
• 0.7 L propane × (4 liter water vapor / 1 liter propane ) = 2.8 Liters of Water Vapor
Answer:
a) 0.61 mol
Explanation:
165.3718 g Rubidium Bromide = 1 mol
100 g Rubidium Bromide = 1/165.3718 x 100
= 0.61 mol
Answer:c
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Answer:
6.0 L
Explanation:
Use the dilution equation M1V1 = M2V2
M1 = 0.075 M
V1 = 200 L
M2 = 2.5 M
V2 = ?
Solve for V2 --> V2 = M1V1/M2
V2 = (0.075 M)(200 L) / (2.5 M) = 6.0 L
