Answer:
The distance between the two objects must be squared.
Explanation:
Gravitational force always act between two objects that have mass. The gravitational force is a weak force and attractive in nature.
The force of pull depends on the masses of the two objects and the distance between them.
The formula to calculate gravitational force between two objects having masses 'm' and 'M' and separated by a distance 'd' is given as:
![F_g=\frac{GmM}{d^2}](https://tex.z-dn.net/?f=F_g%3D%5Cfrac%7BGmM%7D%7Bd%5E2%7D)
Where, 'G' is called the universal gravitational constant and its value is equal to
.
Now, from the above formula, it is clear that, the force of gravitation is inversely proportional to the square of the distance between the two objects.
Thus, the quantity that must be squared in the equation of gravitational force between two objects is the distance 'd'.
Answer:
16. 68.18 Km/h
17. 3 miles.
Explanation:
16. Determination of the speed
Distance travelled = 150 Km
Time = 2.2 hours
Speed =?
Speed is simply defined as the distance travelled with time. Mathematically, it is expressed as:
Speed = Distance / time
With the above formula, we can obtain the speed as follow:
Distance travelled = 150 Km
Time = 2.2 hours
Speed =?
Speed = Distance /time
Speed = 150 / 2.2
Speed = 68.18 Km/h
17. Determination of the distance.
Speed = 3 mph
Time = 1 hour
Distance =?
Speed = Distance /time
3 = distance / 1
Distance = 3 miles
Answer:
Option D: 1.5in in front of the target
Explanation:
The object distance is
.
Because the surface is flat, the radius of curvature is infinity .
The incident index is
and the transmitted index is
.
The single interface equation is ![\frac{n_i}{y}+\frac{n_t}{y^i}=\frac{n_t-n_i}{r}](https://tex.z-dn.net/?f=%5Cfrac%7Bn_i%7D%7By%7D%2B%5Cfrac%7Bn_t%7D%7By%5Ei%7D%3D%5Cfrac%7Bn_t-n_i%7D%7Br%7D)
Substituting the quantities given in the problem,
![\frac{\frac{4}{3}}{6in}+\frac{1}{y^i}= 0](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cfrac%7B4%7D%7B3%7D%7D%7B6in%7D%2B%5Cfrac%7B1%7D%7By%5Ei%7D%3D%200)
The image distance is then ![y^i=-\frac{18}{4}in =-4.5in](https://tex.z-dn.net/?f=y%5Ei%3D-%5Cfrac%7B18%7D%7B4%7Din%20%3D-4.5in)
Therefore, the coin falls
in front of the target