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harkovskaia [24]
4 years ago
13

A moving walkway has a speed of .4 m/s to the east. A stationary observer sees a man walking on the walkway with a velocity of 3

.0 m/s to the east. What's the mans velocity relative to the moving walkway?
Physics
1 answer:
SVEN [57.7K]4 years ago
8 0

Explanation:

Vnet = 0.4m/s - 3.0m/s = - 2.6m/s

so the man walks 2.6m/s towards the west

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what can you say about the motion of an object if its speed time graph is a straight line parallel to the time axis ? Also draw
MaRussiya [10]

Answer:

It says about the motion and the graph of the object is stationary, basically travelling at the same speed at any time of the graph. It will never change.

Explanation:

To draw a diagram:

1. Draw an object and represent the speed as stationary and constant at any time.

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3 years ago
Physics help please:Explain the mechanism by which AC (alternating current) through the primary circuit of a transformer produce
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A short, thick wire is the best conductor. True or false?
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7 0
3 years ago
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An electron moves in a region where the magnetic field is uniform and has a magnitude of 80 μT. The electron follows a helical p
sladkih [1.3K]

Answer:

3.4 x 10⁴ m/s

Explanation:

Consider the circular motion of the electron

B = magnetic field = 80 x 10⁻⁶ T

m = mass of electron = 9.1 x 10⁻³¹ kg

v  = radial speed

r = radius of circular path = 2 mm = 0.002 m

q = magnitude of charge on electron = 1.6 x 10⁻¹⁹ C

For the circular motion of electron

qBr = mv

(1.6 x 10⁻¹⁹) (80 x 10⁻⁶) (0.002) = (9.1 x 10⁻³¹) v

v = 2.8 x 10⁴ m/s

Consider the linear motion of the electron :

v' = linear speed

x = horizontal distance traveled = 9 mm = 0.009 m

t = time taken = \frac{2\pi m}{qB} = \frac{2\pi (9.1\times 10^{-31})}{(1.6\times 10^{^{-19}})(80\times 10^{-6})} = 4.5 x 10⁻⁷ sec

using the equation

x = v' t

0.009 = v' (4.5 x 10⁻⁷)

v' = 20000 m/s

v' = 2 x 10⁴ m/s

Speed is given as

V = sqrt(v² + v'²)

V = sqrt((2.8 x 10⁴)² + (2 x 10⁴)²)

v = 3.4 x 10⁴ m/s

6 0
4 years ago
A big league hitter attacks a fastball! The ball has a mass of 0.16 kg. It is pitched at 38 m/s. After the player hits the ball,
Strike441 [17]
Momentum = (mass) x (velocity)
Original momentum before the hit = 
                   (0.16 kg) x (38 m/s) this way <==
               =             6.08 kg-m/s  this way <==
Momentum after the hit = 
                   (0.16) x (44 m/s) that way  ==>
               =           7.04 kg-m/s  that way ==>
Change in momentum = (6.08 + 7.04) =  13.12 kg-m/s  that way ==> .-----------------------------------------------
Change in momentum = impulse.
                                   Impulse = (force) x (time the force lasted)
                          13.12 kg-m/s  = (force) x (0.002 sec)
  (13.12 kg-m/s) / (0.002 sec)  =  Force
             6,560 kg-m/s² = 6,560 Newtons  =  Force    
                            ( about 1,475 pounds  ! ! ! )
 Hoped this helped!! ☺
4 0
4 years ago
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