A moving walkway has a speed of .4 m/s to the east. A stationary observer sees a man walking on the walkway with a velocity of 3
1 answer:
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The gravitational force between the two objects A) It increases.
Explanation:
The gravitational force between two objects is given by:
(1)
where
G is the gravitational constant
are the masses of the two objects
r is the separation between the objects
In this problem, object A and object B are initially at a distance of
r = 100 m
And at that distance, the force between them is
F
Later, object A gains some mass. We notice from eq.(1) that the gravitational force is directly proportional to the mass: therefore, if the mass of either of the two objects increases, then the gravitational force between them also increases. Therefore, the new force will be larger than the original force:
F' > F
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Answer:
The spacing is 5.15 μm.
Explanation:
Given that,
Electron with energy = 25 eV
Wave length = 0.25 nm
Separation d= 0.16 mm
Distance D=3.3 m
We need to calculate the spacing
Using formula of width
Put the value into the formula
Hence, The spacing is 5.15 μm.