Answer:
I don't really get the options but it favoures the reactant side.
Explanation:
Increasing pressure favours the side with fewer moles of gas while decreasing pressure favours the side with the more moles of gas. E.g
If there is 0 moles of gas particles in the reactant side and 1 mole of gas particle in the product side, increasing pressure favours the reactants while decreasing pressure favours the product side.
With the explanations I have made, I hope the question is now clear to you.
Answer:
See explanation below
Explanation:
In both cases the central atoms, C in CHCl₃ and O in H₂O, are sp³ hybridized .
Since they are sp³ hybridized we predict an angle between the H-C-Cl and H-O-H of 109.5 º ( tetrahedral ), but two of the sp³ orbitals in water are occupied by lone pairs.
These lone pairs do excercise more repulsion ( need more room ) than the bonds oxygen is making with hydrogen.
As a consequence of this repulsion the angles H-O-H are less than the predicted 109.5º in tetrahedra. ( Actually is 104.5 º)
C I believe it is and I think that because I got it right
Metallic (w) with a boiling point of 566”
