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3 years ago

How does a stage 2 of cellular respiration benefit a cell?

Chemistry

2 answers:

AVprozaik [17]3 years ago

7 0

Answer:

The second stage of cellular respiration is the “Krebs Cycle”. This is a catabolic reaction that occurs within the cells. In cells, the energy is produced and stored in the form of ATP.

natima [27]3 years ago

6 0

The cells are produced and stored in atp

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Whats minimum temperature for scrabble eggs

Sonbull [250]

Answer:

of 160° F. Scrambled eggs need to be cooked until firm throughout with no visible liquid egg remaining.

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3 years ago

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How many moles of magnesium are needed to react with 3.0 mol of O2?

labwork [276]

Answer:

2 moles

Explanation:

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3 years ago

1. To calculate the molarity of a solution, you need to know the moles of solute and the

evablogger [386]

Answer:

O volume of the solution

Explanation:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / volume of solution in L

For example:

if we dissolve the 1 mole of NaCl to make the solution of volume 2 L. The molarity of solution is,

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3 years ago

Which tool can be used to measure the volume of a liquid to one decimal place?

pentagon [3]

The tool to measure the liquid is a measuring cylinder.

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For the Zn - Cu^2+ voltaic cell Zn(s) + Cu^2+(aq, 1M) + Cu(s) E degree _cell = 1.10 V Given that the standard reduction potentia

Fittoniya [83]

Answer : The value of $E^o_{(Cu^{2+}/Cu)}$ is, 0.34 V

Explanation :

Here, copper will undergo reduction reaction will get reduced. Zinc will undergo oxidation reaction and will get oxidized.

The oxidation-reduction half cell reaction will be,

Oxidation half reaction: $Zn\rightarrow Zn^{2+}+2e^-$

Reduction half reaction: $Cu^{2+}+2e^-\rightarrow Cu$

Oxidation reaction occurs at anode and reduction reaction occurs at cathode. That means, gold shows reduction and occurs at cathode and chromium shows oxidation and occurs at anode.

The overall balanced equation of the cell is,

$Zn+Cu^{2+}\rightarrow Zn^{2+}+Cu$