The volume of a gas that occupies 9 L at a temperature of 325K is 12.46L.
<h3>How to calculate volume?</h3>
The volume of a given gas can be calculated using the following Charle's law equation:
V1/T1 = V2/T2
Where;
- T1 = initial temperature
- T2 = final temperature
- V1 = initial volume
- V2 = final volume
- V1 = 9L
- V2 = ?
- T1 = 325K
- T2 = 450K
9/325 = V2/450
325V2 = 4050
V2 = 4050/325
V2 = 12.46L
Therefore, the volume of a gas that occupies 9 L at a temperature of 325K is 12.46L.
Learn more about volume at: brainly.com/question/2817451
Answer:
HCl 1.Polar 2.soluble highly
O2 1.non-polar 2.highly soluble
CaCl2 1.Ionic 2.insoluble
N2 1.non polar 2.soluble highly
C2h6 1.non polar 2.insoluble
KNO3 1.ionic 2.Soluble
The brother is represented by variable b.
The sister is represented by the variable s.
This means:
b+s=26
Answer:
it's sodium chloride I believe
Explanation:
