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kipiarov [429]
3 years ago
8

Which of the following conditions creates the largest waves?

Chemistry
2 answers:
PilotLPTM [1.2K]3 years ago
8 0

Answer:

B

Explanation:

k-12 test

SashulF [63]3 years ago
6 0

Answer:

strong winds that blow in short spurts over a small distance

Explanation:

Generally, the most common factor that causes the largest waves in the ocean is winds. this is also called wind-driven waves of the ocean when the surface wind flows on the surface of the ocean, this disturbance creates the friction between surface wind and surface of the ocean which creates waves in the ocean

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What problem could happen if deep sea divers used pure oxygen in their tanks?
AysviL [449]
Hi there!

Deep sea divers CANNOT use pure oxygen in their tanks. Pure oxygen is deadly, and can kill them. This would be called Oxygen toxicity

Hope this helps you!

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3 years ago
A business owned and run by one person is a
S_A_V [24]
A business that is owned and run by one person is a sole proprietorship.
5 0
3 years ago
John Dalton and Antoine Lavoisier were alchemists who tried to convert diamonds to gold.
larisa86 [58]
This is false. They were both chemists and they made many discoveries such as realizing that charcoal and diamond are different forms of the same element and proposing an atomic theory, but they never tried to turn diamonds to gold.
8 0
3 years ago
Read 2 more answers
Upper n subscript 2 (g) plus 3 upper H subscript 2 (g) double-headed arrow 2 upper N upper H subscript 3 (g). At equilibrium, th
artcher [175]

Answer:

The <u>equilibrium constant</u> is:

              k_c=0.0030M^{-2}

Explanation:

The correct equation is:

  •   N₂(g)    +    3H₂(g)    ⇄    2NH₃(g)

Thus, with the equilibrium concentrations you can calculate the equilibrium constant, Kc.

The equation for the equilibrium constant is:

         k_c=\dfrac{[NH_3]^2}{[N_2]\cdot [H_2]^3}

Substituting:

        k_c=\dfrac{(0.105M)^2}{(1.1M)\cdot (1.50M)^3}

         k_c=0.0030M^{-2}

6 0
3 years ago
three moles of sodium carbonate are mixed with two moles of lead nitrate in aqueous solution, leading to formation of a solid pr
aleksandrvk [35]

There are 4 moles of spectator ions that remain in solution.

The equation of the reaction is;

Na2CO3(aq) + Pb(NO3)2(aq) -------> PbCO3(s) + 2NaNO3(aq)

We have to determine the limiting reactant. This is the reactant that yields the least amount of product. Note that the spectator ions are Na^+ and NO3^- that form NaNO3.

For Na2CO3

1 mole of Na2CO3 yields 2 moles of NaNO3

3 moles of Na2CO3 yields  3 × 2/1 = 6 moles of NaNO3

For Pb(NO3)2

1 mole of Pb(NO3)2 yields 2 moles of NaNO3

2 moles of Pb(NO3)2 yields 2 × 2/1 = 4 moles of NaNO3

We can see that Pb(NO3)2 is the limiting reactant.

Since [NaNO3] = [Na^+] = [NO3^-], it follows that there are 4 moles of spectator ions that remain in solution.

Learn more: brainly.com/question/22885959

6 0
2 years ago
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