In order to calculate the amount of heat energy required to melt 347 grams of ice, we need to will apply the equation:
Q
= ml, where m is the mass of substance and l is its latent heat of
fusion. For ice, the latent heat of fusion is 334 joules per gram.
Therefore:
Q = 347 x 334
Q = 112,558 joules of energy
Hope this helped.
Answer:
The thermodynamic parameter which is of significance in this case is the 'Reduction Potential' for molecular bromine which is ~ +1.1 v vs N.H.E. In other words, it is a strong oxidizing agent. The bromine will oxidize sulfur compounds in which the valence of sulfur is lower than six to sulfate.
There are many possible reactions. Here is one possible example:
Na2 S2O3 + 4Br2 + 5 H2O = 2NaHSO4 + 8 HBr
I got a 4 out of 1. not 100 percent sure if this is the right answer but i put 1,2,1,2
Maybe sodium? becasue its an element and I would like some points... sorryy:((((
