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Nimfa-mama [501]
2 years ago
7

A current of 15.0 A flows through an electric heater operating on 120 V. Compute the power consumption of the electric heater.

Physics
1 answer:
Rzqust [24]2 years ago
5 0

Answer:

There will be 1800 W power consumption in heater

Explanation:

We have given current flowing in the heater I = 15 A

Voltage on which heater is operating V = 120 volt

We have to find the power consumption in the heater

We know that power consumption is given by P = VI

So power consumption in heater = 120 × 15 = 1800 W

So there will be 1800 W power consumption in heater

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Which of the following is an implication of the law of inertia?
Thepotemich [5.8K]

Answer:

A

Explanation:

An object in motion will stay in motion unless acted upon by an external force.

Say you rolled a ball on the ground, eventually it will stop because of friction and gravity

7 0
3 years ago
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A 5.00 kg crate is on a 21.0 degree hill. Using X-Y axes tilted down the plane, what is the y-component of the normal force?
Rama09 [41]

Answer:

The y-component of the normal force is 45.74 N.

Explanation:

Given that,

Mass of the crate, m = 5 kg

Angle with hill, \theta=21^{\circ}

We need to find the y component of the normal force. We know that the y component of the normal force is given by :

F_y=F\ \cos\theta\\\\F_y=mg\ \cos\theta\\\\F_y=5\times 9.8\ \cos(21)\\\\F_y=45.74\ N

So, the y-component of the normal force is 45.74 N. Hence, this is the required solution.

7 0
2 years ago
1 point
Oduvanchick [21]
The distance it traveled is 147
5 0
2 years ago
the velocity (v) of a tranvas wave in a string is related to tension (T) the mass (M) and the length (L) of de string by the rel
Lana71 [14]

1

Explanation:

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6 0
3 years ago
1.0 liter of 20c water is mixed with 4 liters of 40c water. What will be the temperature of this mixture
Virty [35]

Answer:

36°C

Explanation:

Heat gained by the cold water = heat lost by the warm water

mCΔT = mCΔT

(1000 g) (4.184 J/g/K) (T − 20°C) = (4000 g) (4.184 J/g/K) (40°C − T)

1000 (T − 20°C) = 4000 (40°C − T)

T − 20°C = 4 (40°C − T)

T − 20°C = 160°C − 4T

5T = 180°C

T = 36°C

8 0
3 years ago
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