Given the index of refraction, n and speed of light in the vacuum, c, we can solve for the speed of light in the transparent substance by the equation below.
n = c / v
where v is our unknown.
Substituting the known values,
1.7 = (3 x 10^8 m/s) / v
The value of v is equal to 1.76 x 10^8 m/s.
In a nuclear power plant, you start off with uranium (nuclear energy), and a lot of that nuclear energy is released by heat energy. Heat then boils water and drives a turbine for a generator, which creates kinetic energy, which produces electrical energy.
In other words, your answer is B.
Answer:
37 W
Explanation:
Power is the time rate of dissipation or absorbing energy. The power supplied or absorbed by an element is the product of the current flowing through the element and the voltage across the element. Power is measured in watts. If the power is positive then it is absorbed by the element and if it is negative then it is supplied by the element.
Power = voltage * current
For element A: Power = 36 V * -4 A = -144 W
For element B: Power = -20 V * -4 A = 80 W
For element C: Power = -24 V * 4 A = -94 W
For element D: Power = -80 V * -1.5 A = 120 W
For element E: Power = 30 V * 2.5 A = 75 W
The total power developed in the circuit = sum of power through the element = (-144 W) + 80 W + (-94 W) + 120 W + 75 W = 37 W
Answer:
2683.3N
Explanation:
According to coulombs law which states that "the force of attraction existing between two charge q1 and q2 is directly proportional to the product of the charges and inversely proportional to the square of the distance (d) between them. Mathematically |F|= k|q1| |q2| /d² where;
F is the force of attraction between the charges
q1 and q2 are the charges
d is the distance between them
k is the coulombs constant
Given |q1|= 38.9 × 10^-6C and |q2| = 27.6399×10^-6C d = 6cm = 0.06m
k = 8.98755 × 109 Nm² /C²
Substituting the given data's in the equation we have;
|F| = 8.98755 × 10^9×38.9×10^-6×27.6399×10^-6/0.06²
|F| = 9.66/0.06²
|F| = 9.66/0.0036
|F| = 2683.3N
The magnitude of the force will be 2683.3N
Note that the modulus of the charges changes negative value of q2 to positive value. The opposite signs of the charges doesn't affect the final calculation, it only tells the force of attraction or repulsion between the charges. Since they are unlike charges, they will attract each other in the field.
