Answer:
The dimensionality of B is <em>length</em> per cubic <em>time</em>.
Explanation:
Units for displacement and time are <em>length</em> ![[L]](https://tex.z-dn.net/?f=%5BL%5D)
and <em>time</em> ![[T]](https://tex.z-dn.net/?f=%5BT%5D)
, respectively. Then, formula can be tested for dimensional analysis as follows:
![[L] = B\cdot [T]^{3}](https://tex.z-dn.net/?f=%5BL%5D%20%3D%20B%5Ccdot%20%5BT%5D%5E%7B3%7D)
Now, let is clear 
to determine its units:
![B = \frac{[L]}{[T]^{3}}](https://tex.z-dn.net/?f=B%20%3D%20%5Cfrac%7B%5BL%5D%7D%7B%5BT%5D%5E%7B3%7D%7D)
The dimensionality of B is <em>length</em> per cubic <em>time</em>.
<h2>
<u>KINETIC ENERGY</u></h2>
<h3>Problem:</h3>
» A 2kg mass is moving at 3m/s. What is its kinetic energy?
<h3>Answer:</h3>
— — — — — — — — — —
<h3>Formula:</h3>
To calculate the velocity of a kinetic energy, we can use formula
where,
- v is the velocity in m/s
- KE is the kinetic energy in J (joules)
- m is the mass in kg
— — —
Based on the problem, the givens are:
- KE (Kinetic energy) = ? (unknown)
- m (mass) = 2 kg
- v (velocity) = 3 m/s
<h3>Solution:</h3>
To get the velocity, substitute the givens in the formula above then solve.
Therefore, the kinetic energy is 9 Joules.
Answer is B- 200 m
Given:
m (mass of the car) = 2000 Kg
F = -2000 N
u(initial velocity)= 20 m/s.
v(final velocity)= 0.
Now we know that
<u>F= ma</u>
Where F is the force exerted on the object
m is the mass of the object
a is the acceleration of the object
Substituting the given values
-2000 = 2000 × a
a = -1 m/s∧2
Consider the equation
<u>v=u +at</u>
where v is the initial velocity
u is the initial velocity
a is the acceleration
t is the time
0= 20 -t
t=20 secs
s = ut +1/2(at∧2)
where s is the displacement of the object
u is the initial velocity
t is the time
v is the final velocity
a is the acceleration
s= 20 ×20 +(-1×20×20)/2
<u>s= 200 m</u>
Answer:
840 cm
Explanation:
Note: A hydraulic press operate based on pascal's principle.
From pascal's principle
W₁/d₁ = W₂/d₂...................... Equation 1
Where W₁ and W₂ are the first and second weight, and d₁ and d₂ are the first and second diameter of the piston.
make d₁ the subject of the equation
d₁ = W₁×d₂/W₂................ Equation 2
Given: W₁ = 2100 kg, W₂ = 25 kg, d₂ = 10 cm = 0.1 m.
Substitute these values into equation 2
d₁ = 2100(0.1)/25
d₁ = 8.4 m
d₁ = 840 cm
