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3 years ago

Is the cell membrane a factory part or worker? Please explain what it does as a factory part or worker

Chemistry

2 answers:

lozanna [386]3 years ago

7 0

Answer:

hey i saw you asked about the kinetic energy lab report on edg and i was wondering if you ever finished it and could send it me plzzzzzzzz

Explanation:

Tema [17]3 years ago

3 0

It is probably a worker bc it lets things in and out of the cell and stops harmful things from entering the cell

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What is the concentration of the hydroxide ion? Given that the concentration of the hydronium ion is 2.3 X 10^-7 M

professor190 [17]

Answer:

4.35 * 10^-8 M

Explanation:

Since the concentration of the hydronium ion= 2.3 X 10^-7 M

And we know that;

[H3O^+] [OH^-] = 1 * 10^-14

[H3O^+] = concentration of the hydronium ion

[OH^-] = concentration of the hydroxide ion

So;

[OH^-] =1 * 10^-14/[ H3O^+]

But [H3O^+] = 2.3 X 10^-7 M

[OH^-] = 1 * 10^-14/2.3 X 10^-7

[OH^-] = 4.35 * 10^-8 M

8 0

3 years ago

What do you think happens to the cells when they do not get the oxygen they need? Why?

ivanzaharov [21]

Answer:

the cells start to deteriorate

Explanation:

the lack of oxygen to your body and cells will cause them to break down.

4 0

3 years ago

How many electrons are in sodium-20?

Eva8 [605]

Answer:

Explanation:

According to the periodic table Sodium (Na) has 11 electrons.

5 0

4 years ago

A 0.245-L flask contains 0.467 mol co2 at 159 °c. Caculate the pressure using Van der Walls equation

AlladinOne [14]

Answer:

The right answer is "60.56 atm".

Explanation:

As we know,

Vander wall's equation is:

⇒ $(P+\frac{n^2 a}{v^2} )(v-nb)=nRT$

or,

⇒ $P=\frac{nRT}{(v-nb)}-\frac{n^2 a}{v^2}$

Here,

a = 3.59 L² atm mol⁻²

b = 0.0427 L mol⁻¹

By putting the values in the above equation, we get

⇒ $P=\frac{0.467\times 0.0821\times 432}{0.245-0.467\times 0.0427}$

$=\frac{(0.467)^2\times 3.49}{(0.245)^2}$

$=73.61-13.05$

$=60.56 \ atm$

8 0

3 years ago

When excess dilute hydrochloric acid was added to sodium sulphite 960 of sulphuric (iv) oxide was produced. calculate the mass o

irakobra [83]

The mass of sodium sulfite that was used will be 1,890 grams.

<h3>Stoichiometric problems</h3>

First, the equation of the reaction:

$NaSO_3 + 2HCl --- > NaCl_2 + H_2O + SO_2$

The mole ratio of SO2 produced and sodium sulfite that reacted is 1:1.

Mole of 960 grams SO2 = 960/64 = 15 moles

Equivalent mole of sodium sulfite that reacted = 15 moles

Mass of 15 moles sodium sulfite = 15 x 126 = 1,890 grams

More on stoichiometric problems can be found here: brainly.com/question/14465605

#SPJ1

3 0

2 years ago