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ivolga24 [154]
3 years ago
13

Help please ;( really don’t understand Chemistry would really appreciate it if can explain to me thank you!

Chemistry
1 answer:
Tanya [424]3 years ago
7 0

Answer:

b)   O₂

d)   CH₄

Explanation:

In a chemical equation, the <u>reactants</u> are the substances that are written on the <u>left side</u>. The reactants react to produce the products. On the right side, the products are written.

The arrow => is used to separate the reactants from the products.

To the left of the arrow, you can see this written:

CH₄ + 2O₂

The plus sign + is used to separate each reactant.

In 2O₂ you can ignore the big 2 because it is a coefficient, which is written to balance the equation.

The reactants are CH₄ and O₂

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How many molecules are in 3.50 moles of H2O<br>​
Debora [2.8K]

Answer:

2.11 x 10²⁴ molecules.

Explanation:

  • <em>It is known that every 1.0 mole of a molecule contains Avogadro's number of molecules (NA = 6.022 x 10²³).</em>

<em><u>Using cross multiplication:</u></em>

1.0 mole of H₂O contains → 6.022 x 10²³ molecules.

3.5 mole of H₂O contains → ??? molecules.

∴ 3.5 mole of H₂O contain = (3.5 mol)(6.022 x 10²³) = 2.11 x 10²⁴ molecules.

5 0
4 years ago
Many portable gas heaters and grills use propane, C3H8(g). Using enthalpies of formation, calculate the quantity of heat produce
Elodia [21]

Answer:  600 kJ

-

Explanation:

                        C₃H₈ (g)  + 5 O₂ (g) =============== 3 CO₂ (g)  +  4 H₂O (l)

Δ⁰Hf   kJ/mol       -104             0                                       -393.5         -285.8

Δ⁰Hcomb C₃H₈ = 3(-393.5) + 4 (-285.80) - (-104)  kJ/mol

Δ⁰Hcomb = 2219.70 kJ/mol

n= m /MW   MW c₃H₈ = 44.1 g/mol

n= 12 g/44.1 g/mol = 0.27 mol

then for 12 g the heat released will be

0.27 mol x 2219.70 kJ/mol =  600 KJ

4 0
3 years ago
Read 2 more answers
what temperature change will be observed if a sample of 100 g of ethylene glycol antifreeze solution (specific heat capacity = 3
ivolga24 [154]

Answer:

1°C temperature change will be observed if a sample of 100 g of ethylene glycol antifreeze solution.

Explanation:

Mass of ethylene glycol = m = 100 g

Specific heat capacity of ethylene glycol = c = 3.5 J/g°C

Change in temperature of ethylene glycol = ΔT

Heat loss by the ethylene glycol = Q = 350 J

Q=mc\Delta T

\Delta T=\frac{Q}{mc}=\frac{350 J}{100 g\times 3.5 J/g^oC}

ΔT = 1°C

1°C temperature change will be observed if a sample of 100 g of ethylene glycol antifreeze solution.

3 0
3 years ago
Calculate the specific heat of a substance when 63j of energy are transferred as heat to an 8.0 g sample to raise it temperature
Flura [38]

The formula for energy or enthalpy is:

E = m Cp (T2 – T1)

where E is energy = 63 J, m is mass = 8 g, Cp is the specific heat, T is temperature

 

63 J = 8 g * Cp * (340 K – 314 K)

<span>Cp = 0.3 J / g K</span>

6 0
4 years ago
Read 2 more answers
The weathered debris in deserts consists mainly of
vampirchik [111]

Answer;

C. unchanged rock and mineral fragments

Explanation;

A large number of landforms and features found in desert environments are formed as the result of weathering. Weathering is defined as the breakdown and deposition of rocks by weather acting in situ

The two main types of weathering which occur in deserts are Mechanical weathering, which is the disintegration of a rock by mechanical forces that do not change the rock's chemical composition and Chemical weathering, which is the decomposition of a rock by the alteration of its chemical composition.

By contrast much of the weathered debris in deserts has resulted from mechanical weathering. Chemical weathering, however, is not completely absent in deserts. Over long time spans,clays and thin soils do form.


7 0
4 years ago
Read 2 more answers
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