If it starts from 0m/s...
s=?
u=0
a=-10
t=8
s=ut +1/2at^2
so s=(0×8)+ (0.5×-10×64)
s=0+(32×-10)
s=32×-10
s=-320metres
Answer:
Δx = 1.2 m
Explanation:
The CHANGE of spring length) (Δx) can be found using PS = ½kΔx²
Δx = √(2PS/k) = √(2(450)/650) = 1.17669... ≈ 1.2 m
The actual length of the spring is unknown as it varies with material type, construction method, extension or compression, and other variables we have no clue about.
#1.
<em>Car </em>1<em> weighs </em>300 kilograms<em> and is moving right at </em>3 meters per second (m/s)
#2.
Law of conservation of momentum
momentum before collorion = momentim after collosion
MV + mv = MV' + mv'
1500x25+ 1000x5
37500 + 15000
In order to persuade the electrons in the wire to flow, you need
a potential difference between the ends of the wire. Then the
electrons will want to get away from the more-negative end and
go to the more-positive end. If both ends of the wire are at the
same potential, then the electrons have no reason to go anywhere,
and they just stay where they are.
Choice-d says this.
Answer:
Explanation:
= magnitude of charge on each proton = 1.6 x 10⁻¹⁹ C
= mass of each proton = 1.67 x 10⁻²⁷ kg
r = distance between the two protons = 1 x 10⁻¹⁵ m
Electric force between the two protons is given as
N
Gravitational force between the two protons is given as
N
Ratio is given as
