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son4ous [18]
3 years ago
7

What is the relation between the weight of a body and acceleraton due to gravity?​

Physics
1 answer:
emmainna [20.7K]3 years ago
6 0

Answer:

All objects on Earth, regardless of their mass, accelerate due to gravity at the same rate - that is, 9.8 m/sec2. The weight of an object can be calculated using the formula for force - F = m * a - where F equals the weight of the object and now the acceleration (a) is the acceleration of gravity (g).

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3 years ago
Pleaseeee Please help, I will love you forever and ever
matrenka [14]

Answer:

The answer to your question is

Explanation:

Data

mass = 0.5kg

T1 = 35

T2 = ?

Q = - 6.3 x 10⁴ J  = - 63000 J

Cp = 4184 J / kg°C

Formula

                        Q = mCp(T2 - T1)

                         T2 = T1 + Q/mCp    

Substitution

                       T2 = 35 - 63000/(0.5 x 4184)

                        T2 = 35 - 63000/2092

                        T2 = 35 - 30.1

                         T2 = 4.9 °C

6 0
3 years ago
describes how the color and texture of a surface affect absorption and reflection of solar radiation?
Wewaii [24]

Most of the radiation, however, is absorbed by the earth's surface. ... Every surface on earth absorbs and reflects energy at varying degrees, based on its color and texture. Dark-colored objects absorb more visible radiation; light-colored objects reflect more visible radiation.

3 0
3 years ago
look at the circuit in the figure. find the current, voltage, and power in each resistor. please list answer
sashaice [31]

Answer:

fhcjctfkbraf gdovtckcrhha6g

6 0
2 years ago
The isomerization of cyclopropane to form propene is a first-order reaction. At 760 K, 85% of a sample of cyclopropane changes t
Nataliya [291]

Answer:

so rate constant  is 4.00 x 10^-4 s^{-1}

Explanation:

Given data

first-order reactions

85% of a sample

changes to propene t =  79.0 min

to find out

rate constant

solution

we know that

first order reaction are

ln [A]/[A]0 = -kt

here [A]0 = 1 and (85%) = 0.85 has change to propene

so that [A] = 1 - 0.85 = 0.15.

that why

[A] / [A]0= 0.15 / 1

[A] / [A]0 = 0.15

here t = (79) × (60s/min) = 4740 s  

so

k = - {ln[A]/[A]0} / t

k = -ln 0.15 / 4740

k = 4.00 x 10^-4 s^{-1}

so rate constant  is 4.00 x 10^-4 s^{-1}

3 0
3 years ago
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