Answer:
The speed of the catapult arm needs to be increased.
Explanation:
If the height needs to stay the same, they can not change the length of the catapult arm because this is the variable that determines the height of the thrown object. To change the horizontal distance the object travels, in other words the object's speed, the rope or counterweigth that pulls the catapult arm can be changed to increase the speed that the object is thrown.
I hope this answer helps.
Answer:
![X=8.44m](https://tex.z-dn.net/?f=X%3D8.44m)
Explanation:
From the question we are told that
Distance b/w A&B ![x=4.80m](https://tex.z-dn.net/?f=x%3D4.80m)
Frequency ![f=134Hz](https://tex.z-dn.net/?f=f%3D134Hz)
Sound speed ![v=343m/s](https://tex.z-dn.net/?f=v%3D343m%2Fs)
Generally the equation for wavelength is mathematically given as
![\lambda=v/f](https://tex.z-dn.net/?f=%5Clambda%3Dv%2Ff)
![\lambda/2=1/2*v/f](https://tex.z-dn.net/?f=%5Clambda%2F2%3D1%2F2%2Av%2Ff)
![\lambda/2=1/2*\frac{343}{135}](https://tex.z-dn.net/?f=%5Clambda%2F2%3D1%2F2%2A%5Cfrac%7B343%7D%7B135%7D)
![\lambda/2=1.27037037](https://tex.z-dn.net/?f=%5Clambda%2F2%3D1.27037037)
Generally the destructive interference X is mathematically given by
![\sqrt{4.8^2 +X^2} -X=1.27037037\\](https://tex.z-dn.net/?f=%5Csqrt%7B4.8%5E2%20%2BX%5E2%7D%20-X%3D1.27037037%5C%5C)
![23.04+BC^2=X^2+1.613+2.54*X](https://tex.z-dn.net/?f=23.04%2BBC%5E2%3DX%5E2%2B1.613%2B2.54%2AX)
Therefore the destructive interference is
![X=8.44m](https://tex.z-dn.net/?f=X%3D8.44m)
Here is your answer
b) ![\huge 1.5× {10}^{11} Hz](https://tex.z-dn.net/?f=%5Chuge%201.5%C3%97%20%7B10%7D%5E%7B11%7D%20Hz%20)
REASON :
We know that
Velocity= Frequency× Wavelength
So,
Frequency= Velocity/wavelength
Here,
V= 3× 10^8 m/s
Wavelength= 2×10^-3 m
Hence,
Frequency= 3×10^8/2×10^-3
= 3/2 × 10^11
= 1.5× 10^11 Hz
HOPE IT IS USEFUL
Answer:
120,000J
Corrected question;
In one hour, coal supplies 500 000 J of energy. The wasted energy amounts to 380 000 J. How much useful energy is produced in one hour?
Explanation:
Given;
Total energy Et = 500,000 J
Wasted Energy Ew = 380,000J
The amount useful energy is the amount of energy that is available for supply.
This can be derived by subtracting the wasted energy from the total energy.
Useful energy = Total Energy - wasted energy
Eu = Et - Ew
Substituting the given values;
Eu = 500,000J - 380,000
Eu = 120,000 J
The amount of useful energy produced in one hour is 120,000 J
What are the "following" devices ? ?
I think they're a list of choices that you have but aren't sharing.
A few devices associated with the reception of various types of
radio signals include the resonant tank, the local oscillator, the
mixer, the detector, the coherer, the discriminator, the parabolic
reflector, the lecher wires, the audio transducer, the demultiplexer,
and ... my personal guess ... the 'antenna' or 'aerial'.