We will use the Cosine Law:
m D² = A² + B² - 2 AB cos D
∠D = 65° + 58° = 123°
m D² = 220² + 140² - 2 * 220 * 140 * cos 123°
m D² = 48,000 + 19,600 + 33,854.72
m D = 319.15 km
After that we will use the Sine Law:
340 / sin 123° = 220 / sin (theta)
sin (theta) = 0.578
∠(theta) = sin^(-1)0.578 = 35.3°
Answer:
The magnitude of the vector D is 319.15 km and points 35.3° south to east.
Answer:
5m/s/s
Explanation:
The units for velocity is m/s.
The units for acceleration is m/s/s
So, Determine the change in velocity and divide it by the time that change took place.
(30m/s - 10m/s)/4s = 20m/s/(4s) = 5m/s/s
The correct option is d
<span>Weight changes depending on distance from the earth, mass does not.
Weight can be defined as the force exerted on an object due to the effects of gravity.
As we move far away from the Earth, the effects of gravity lessen and thus the weight decreases. (But the mass remains constant, because it only depends on the volume and density of the object)
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Answer:
A λ = 97.23 nm
, B) λ = 486.2 nm
, C) λ = 53326 nm
Explanation:
With that problem let's use the Bohr model equation for the hydrogen atom
= -k e² /2a₀ 1/n²
For a transition between two states we have
-
= -k e² /2a₀ (1/
² - 1 / n₀²)
Now this energy is given by the Planck equation
E = h f
And the speed of light is
c = λ f
Let's replace
h c / λ = - k e² /2a₀ (1 /
² - 1 / no₀²)
1 / λ = - k e² /2a₀ hc (1 /
² -1 / n₀²)
Where the constants are the Rydberg constant
= 1.097 10⁷ m⁻¹
1 / λ =
(1 / n₀² - 1 / nf²)
Now we can substitute the given values
Part A
Initial state n₀ = 1 to the final state
= 4
1 / λ = 1.097 10⁷ (1/1 - 1/4²)
1 / λ = 1.0284 10⁷ m⁻¹
λ = 9.723 10⁻⁸ m
We reduce to nm
λ = 9.723 10⁻⁸ m (10⁹ nm / 1m)
λ = 97.23 nm
Part B
Initial state n₀ = 2 final state
= 4
1 / λ = 1.097 10⁷ (1/2² - 1/4²)
1 / λ = 0.2056 10⁻⁷ m
λ = 486.2 nm
Part C
Initial state n₀ = 3
1 / λ = 1,097 10⁷ (1/3² - 1/4²)
1 / λ = 5.3326 10⁵ m⁻¹
λ = 5.3326 10-5 m
λ = 53326 nm
Answer:
the process by which plants and animals
Explanation:
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