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steposvetlana [31]
3 years ago
10

Which part of the sun-layers will you be able to see Northern lights or auroras?. A. Ozonosphere B. Ionosphere C. Exosphere D. T

roposphere
Physics
2 answers:
mina [271]3 years ago
6 0
The ionosphere is the part of the sun-layers which allows us to see the northern lights or auroras. The ionosphere is the most concentrated with ions and charged electrons and reflects radio waves.
BabaBlast [244]3 years ago
4 0

Answer

The answer is ionosphere

Explanation:

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Hi i need answers for this. Thank you!! this is also really important and is due tomorrow at 9am!!
Allushta [10]

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You're four sentences should include about how the roller coaster has the most potential energy at the top of the track, and the opposing energy, "kinetic" has the most kinetic energy when going down the hill.

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3 years ago
How to find the coefficient of kinetic friction on an incline?
PolarNik [594]

Answer:

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2 years ago
A block is attached to a spring, with spring constant k, which is attached to a wall. it is initially moved to the left a distan
Ghella [55]

Answer:

x(t) = d*cos ( wt )

w = √(k/m)

Explanation:

Given:-

- The mass of block = m

- The spring constant = k

- The initial displacement = xi = d

Find:-

- The expression for displacement (x) as function of time (t).

Solution:-

- Consider the block as system which is initially displaced with amount (x = d) to left and then released from rest over a frictionless surface and undergoes SHM. There is only one force acting on the block i.e restoring force of the spring F = -kx in opposite direction to the motion.

- We apply the Newton's equation of motion in horizontal direction.

                             F = ma

                             -kx = ma

                             -kx = mx''

                              mx'' + kx = 0

- Solve the Auxiliary equation for the ODE above:

                              ms^2 + k = 0

                              s^2 + (k/m) = 0

                              s = +/- √(k/m) i = +/- w i

- The complementary solution for complex roots is:

                              x(t) = [ A*cos ( wt ) + B*sin ( wt ) ]

- The given initial conditions are:

                              x(0) = d

                              d = [ A*cos ( 0 ) + B*sin ( 0 ) ]

                              d = A

                              x'(0) = 0

                              x'(t) = -Aw*sin (wt) + Bw*cos(wt)

                              0 = -Aw*sin (0) + Bw*cos(0)

                              B = 0

- The required displacement-time relationship for SHM:

                               x(t) = d*cos ( wt )

                               w = √(k/m)

3 0
3 years ago
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