A. H2O is the substance reduced.
H2O + 2e^(-) →H_2 + 2OH^(-)
The substance that gains electrons is reduced.
Remember OIL <em>RIG </em>(<em>R</em>eduction <em>I</em>s <em>G</em>ain of electrons) and
LEO the lion says <em>GER</em> (<em>G</em>ain of <em>E</em>lectrons is <em>R</em>eduction).
Answer:
8.66 g of Al₂O₃ will be produced
Explanation:
4Al (s) + 3O₂ (g) → 2Al₂O₃ (s)
This is the reaction.
Problem statement says, that the O₂ is in excess, so the limiting reactant is the Al. Let's determine the moles we used.
4.6 g / 26.98 g/mol = 0.170 moles
Ratio is 4:2.
4 moles of aluminum can produce 2 moles of Al₂O₃
0.170 moles of Al, may produce (0.170 .2)/ 4 = 0.085 moles
Let's convert the moles of Al₂O₃ to mass.
0.085 mol . 101.96 g/mol = 8.66 g
Cross contamination can be caused by CARRYING DRINKING GLASSES BY THE RIMS.
Cross contamination refers to the transfer of harmful microbes to foods from various sources. The rim of a drinking glass is where you put your mouth when you are drinking from a glass cup. If one is carrying a drinking glass by the rim, one can easily transfer the dirty in one's hand to the glass and this will be ingested by person who use the cup. Drinking glasses should be carried by holding their bases.
The theoretical yield of Li3N is 20.9 g .
